Example code for building a tree menu (including multi-level menu) in Java
This article mainly introduces the example code for building a tree menu in Java (supporting multi-level menus). It is very good and has reference value. Friends in need can refer to the
renderings: support multi-level menus menu.
Menu entity class:
public class Menu { // 菜单id private String id; // 菜单名称 private String name; // 父菜单id private String parentId; // 菜单url private String url; // 菜单图标 private String icon; // 菜单顺序 private int order; // 子菜单 private List<Menu> children; // ... 省去getter和setter方法以及toString方法 }
Menus generally need to be sorted, we sort according to the order field of Menu:
/* * 排序,根据order排序 */ public Comparator<Menu> order(){ Comparator<Menu> comparator = new Comparator<Menu>() { @Override public int compare(Menu o1, Menu o2) { if(o1.getOrder() != o2.getOrder()){ return o1.getOrder() - o2.getOrder(); } return 0; } }; return comparator; }
Generating tree Method:
public Map<String,Object> findTree(){ Map<String,Object> data = new HashMap<String,Object>(); try {//查询所有菜单 List<Menu> allMenu = menuDao.findTree(); //根节点 List<Menu> rootMenu = new ArrayList<Menu>(); for (Menu nav : allMenu) { if(nav.getParentId().equals("0")){//父节点是0的,为根节点。 rootMenu.add(nav); } } /* 根据Menu类的order排序 */ Collections.sort(rootMenu, order()); //为根菜单设置子菜单,getClild是递归调用的 for (Menu nav : rootMenu) { /* 获取根节点下的所有子节点 使用getChild方法*/ List<Menu> childList = getChild(nav.getId(), allMenu); nav.setChildren(childList);//给根节点设置子节点 } /** * 输出构建好的菜单数据。 * */ data.put("success", "true"); data.put("list", rootMenu); return data; } catch (Exception e) { data.put("success", "false"); data.put("list", new ArrayList()); return data; } }
Get submenu:
/** * 获取子节点 * @param id 父节点id * @param allMenu 所有菜单列表 * @return 每个根节点下,所有子菜单列表 */ public List<Menu> getChild(String id,List<Menu> allMenu){ //子菜单 List<Menu> childList = new ArrayList<Menu>(); for (Menu nav : allMenu) { // 遍历所有节点,将所有菜单的父id与传过来的根节点的id比较 //相等说明:为该根节点的子节点。 if(nav.ParentId().equals(id)){ childList.add(nav); } } //递归 for (Menu nav : childList) { nav.setChildren(getChild(nav.getId(), allMenu)); } Collections.sort(childList,order());//排序 //如果节点下没有子节点,返回一个空List(递归退出) if(childList.size() == 0){ return new ArrayList<Menu>(); } return childList; }
The final JSON string returned is as follows:
{ "success": "true", "list": [ { "id": "1", "name": "Java", "parentid": "0", "url": "http://www.php.cn", "order": 1, "children": [ { "id": "2", "name": "并发编程", "parentid": "1", "url": "http://www.php.cn", "order": 1, "children": [] }, { "id": "3", "name": "多线程", "parentid": "1", "url": "http://www.php.cn", "order": 2, "children": [ "id": "4", "name": "Thread", "parentid": "3", "url": "http://www.php.cn", "order": 1, "children":[] ] } ] }, { "id": "5", "name": "Python", "parentid": "0", "url": "http://www.php.cn", "order": 2, "children": [] } ] }
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