


First introduce the data table structure involved, four fields:
The code is as follows:
uid
session_id
login_time
logout_time
1. The client regularly sends requests to the server. The implementation method is to insert uid, session_id, login_time into a record after the user logs in, and then set a timer in the client js, such as sending a request to the server every 10 minutes to achieve the purpose of updating the logout time. , of course, the shorter the interval is set, the more accurate the data may be, but the corresponding system load will be higher. This can be set to an appropriate value based on the actual situation. This method is widely used in webgames, because almost all requests in webgames are ajax requests, and there is no need to refresh the page. Once the page is refreshed, the timer loses its value, which is also the limitation of this method.
2. Set up a scheduled polling script on the server. This method is to write a scheduled execution script on the server side, for example, execute it once every 5 minutes. Based on the records in the database, it is judged whether the session_id of each session still exists on the server. If it exists, logout_time is updated. If it does not exist, it is skipped. This can also accurately count online time, but the disadvantage is that you need to have control of the server, otherwise you cannot set a timing script. Linux systems can do this through crontab, and Windows systems can do it through scheduled tasks. If you just bought a virtual host, then this method is not suitable for you either.
3. Update the logout time every time the user performs an activity. In this way, when the user is inactive or logs out, the logout time will naturally exist in the database. This is also the solution that this article focuses on. The implementation method is given below.
First, after the user successfully logs in, record his uid and session_id, and use the current time as the login time, and the current time of 600s as the logout time, and insert it into the database.
The code is as follows:
Copy code The code is as follows:
$uid = $_SESSION[uid] = $info[id];
$session_id = $_SESSION[session_id] = session_id();
$login_time = time();
$ logout_time = time() 600;
$sql = "INSERT INTO member_login (uid,session_id,login_time,logout_time) values($uid,$session_id,$login_time,$logout_time)";
mysql_query($sql);
Then Every time the user acts, that is, every time he clicks on a page, if the session exists, that is, when he is logged in, the user's logout time is updated
The code is as follows:
if($_SESSION[uid]){
$uid = $_SESSION[ uid];
$session_id = $_SESSION[session_id];
$logout_time = time() 600;
$sql = "UPDATE member_login SET logout_time=$logout_time WHERE uid=$uid AND session_id=$session_id";
mysql_query($ sql);
}
The advantage of this method is that it is relatively simple to implement, can be applied to most websites, has no additional server requirements, and can also accurately count users’ online time.
The disadvantages are also obvious. It increases the update operation of the database and increases the load on the system, but it should not be a problem for small and medium-sized websites.

php把负数转为正整数的方法:1、使用abs()函数将负数转为正数,使用intval()函数对正数取整,转为正整数,语法“intval(abs($number))”;2、利用“~”位运算符将负数取反加一,语法“~$number + 1”。

实现方法:1、使用“sleep(延迟秒数)”语句,可延迟执行函数若干秒;2、使用“time_nanosleep(延迟秒数,延迟纳秒数)”语句,可延迟执行函数若干秒和纳秒;3、使用“time_sleep_until(time()+7)”语句。

php除以100保留两位小数的方法:1、利用“/”运算符进行除法运算,语法“数值 / 100”;2、使用“number_format(除法结果, 2)”或“sprintf("%.2f",除法结果)”语句进行四舍五入的处理值,并保留两位小数。

php字符串有下标。在PHP中,下标不仅可以应用于数组和对象,还可应用于字符串,利用字符串的下标和中括号“[]”可以访问指定索引位置的字符,并对该字符进行读写,语法“字符串名[下标值]”;字符串的下标值(索引值)只能是整数类型,起始值为0。

判断方法:1、使用“strtotime("年-月-日")”语句将给定的年月日转换为时间戳格式;2、用“date("z",时间戳)+1”语句计算指定时间戳是一年的第几天。date()返回的天数是从0开始计算的,因此真实天数需要在此基础上加1。

在php中,可以使用substr()函数来读取字符串后几个字符,只需要将该函数的第二个参数设置为负值,第三个参数省略即可;语法为“substr(字符串,-n)”,表示读取从字符串结尾处向前数第n个字符开始,直到字符串结尾的全部字符。

方法:1、用“str_replace(" ","其他字符",$str)”语句,可将nbsp符替换为其他字符;2、用“preg_replace("/(\s|\ \;||\xc2\xa0)/","其他字符",$str)”语句。

php判断有没有小数点的方法:1、使用“strpos(数字字符串,'.')”语法,如果返回小数点在字符串中第一次出现的位置,则有小数点;2、使用“strrpos(数字字符串,'.')”语句,如果返回小数点在字符串中最后一次出现的位置,则有。


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