Codeforces Beta Round #4 (Div. 2 Only) B. Before an Exam_html/css_WEB-ITnose

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The main idea of ​​the question:

Requires t hours of study in n days, Give the minimum and maximum time you can study each day. Ask if it can be implemented and if the timetable can be output.

Solution ideas:

A simple question, guaranteed to be greedy directly within the range.

Here is the code:

#include <set>#include <map>#include <queue>#include <math.h>#include <vector>#include <string>#include <stdio.h>#include <string.h>#include <stdlib.h>#include <iostream>#include <cctype>#include <algorithm>#define eps 1e-10#define pi acos(-1.0)#define inf 107374182#define inf64 1152921504606846976#define lc l,m,tr<<1#define rc m + 1,r,tr<<1|1#define zero(a) fabs(a)<eps#define iabs(x)  ((x) > 0 ? (x) : -(x))#define clear1(A, X, SIZE) memset(A, X, sizeof(A[0]) * (min(SIZE,sizeof(A))))#define clearall(A, X) memset(A, X, sizeof(A))#define memcopy1(A , X, SIZE) memcpy(A , X ,sizeof(X[0])*(SIZE))#define memcopyall(A, X) memcpy(A , X ,sizeof(X))#define max( x, y )  ( ((x) > (y)) ? (x) : (y) )#define min( x, y )  ( ((x) < (y)) ? (x) : (y) )using namespace std;struct node{    int min1,max1;}da[35];int main(){    int d,t,uplim=0,downlim=0;    scanf("%d%d",&d,&t);    for(int i=0;i<d;i++)    {        scanf("%d%d",&da[i].min1,&da[i].max1);        downlim+=da[i].min1;        uplim+=da[i].max1;    }    if(uplim<t||downlim>t)    {        puts("NO");    }    else    {        puts("YES");        t-=downlim;        for(int i=0;i<d;i++)        {            if(t>=da[i].max1-da[i].min1)            {                printf("%d ",da[i].max1);                t-=da[i].max1-da[i].min1;            }            else if(t==0)            {                printf("%d ",da[i].min1);            }            else if(t<da[i].max1-da[i].min1)            {                printf("%d ",t+da[i].min1);                t=0;            }        }    }    return 0;}