有一个API,需要用表单pos到一个地址,然后获取返回的数据。
<form action="https://dnsapi.cn/Record.List" method="post"> <input type="text" value="登陆邮箱地址" name="login_email"> <input type="passwd" value="登陆密码" name="login_password"> <input type="text" value="ID" name="format"> <input type="submit"> <form>
这个我点击提交以后就会链接到 上面的API地址,如何把API地址返回的值直接显示在本页面呢,谢谢
回复讨论(解决方案)
需要用ajax提交,返回的内容都在JavaScript变量中
你可以使用jquery的ajax函数来实现, 文档在这是http://api.jquery.com/jQuery.ajax/
你如果是想在PHP端直接实现的话,你可以采用curl、socket等去模拟提交后抓取返回值。
你如果是想在PHP端直接实现的话,你可以采用curl、socket等去模拟提交后抓取返回值。
curl正解
$.ajax({
type: "POST",
url:"https://dnsapi.cn/Record.List",
data: $("#formid").serialize(),
success: function(data){
alert(data);
}
});

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