PHP查询数据库数据时出现错误
PHP 查询数据库books中的books表时出现以下错误!
Notice: Trying to get property of non-object in D:\wamp\Apache\htdocs\php\results.php on line 33
Fatal error: Call to a member function fetch_assoc() on a non-object in D:\wamp\Apache\htdocs\php\results.php on line 35
代码如下:
- PHP code
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --> <title> Book-O-Rama Catalog Search</title> <h1 id="Book-O-Rama-Catalog-Search">Book-O-Rama Catalog Search</h1> <?php //create short variable names $searchtype=$_POST['searchtype']; $searchterm=trim($_POST['searchterm']); if (!$searchtype || !$searchterm) { exit('You have not entered search detais,please go back again'); } if (!get_magic_quotes_gpc()){ $searchtype=addslashes($searchtype); $searchterm=addslashes($searchterm); } @ $db=new mysqli('localhost','root','password','books'); if (mysqli_connect_errno()){ echo "could not connect to database,please try again later.".mysqli_connect_errno(); exit; }else { $sql ="select * from books where".$searchtype."like'%".$searchterm."%'"; $result=$db->query($sql); $num_result=$result->num_rows; for ($i=0;$ifetch_assoc(); echo "<p>".($i+1)."title:"; echo htmlspecialchars(stripslashes($row['author'])); echo "Author:".stripslashes($row->newsauthor); echo "ISBN:".stripslashes($row->newsISBN); echo "price:".stripslashes($row->newsprice)."</p>"; } } $result->free(); $db->colse(); ?>
上述问题那微微大虾能给个解决方案!
------解决方案--------------------
- PHP code
$sql ="select * from books where ".$searchtype." like '%".$searchterm."%'"; if ($result=$db->query($sql)) { $num_result=$result->num_rows; for ($i=0;$ifetch_assoc(); echo "<p>".($i+1)."title:"; echo htmlspecialchars(stripslashes($row['author'])); echo "Author:".stripslashes($row->newsauthor); echo "ISBN:".stripslashes($row->newsISBN); echo "price:".stripslashes($row->newsprice)."</p>"; } }else{ echo "fail."; exit; } <div class="clear"> </div>

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