php通过表单提交参数查询
如题 想做个简单的查询系统:
现在搞了个没有表单的,代码如下:
- PHP code
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --><?php $con = mysql_connect("localhost","username","password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("cbd", $con); $result = mysql_query("SELECT date,ip, count(ip) as count FROM syn_number WHERE date like '%05-08%' group by ip order by count desc limit 10"); echo "<table border='1'> <tr> <th>date</th> <th>ip</th> <th>number</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['FirstName'] . "</td>"; echo "<td>" . $row['LastName'] . "</td>"; echo "</tr>"; } echo ""; mysql_close($con); ?>
现在想把这段代码sql语句中的 05-08 和最后的limit 10 数字10 改为用表单提交,每次我可以输入
0508最好是可以输入一个范围 比如0508到0510 这样
请问该如何实现?
用表单的话 是要再搞个html文件了?
------解决方案--------------------
$limit = ' LIMIT ' . $_POST['start'] . ',' . $_POST['end'];
$sql = "SELECT date,ip, count(ip) as count FROM syn_number WHERE date like '%05-08%' group by ip order by count desc $limit";
$result = mysql_query($sql);
-----------
html
Limit:
------解决方案--------------------
SELECT date,ip, count(ip) as count FROM syn_number
你从数据只获得三列数据 date, ip, count 哪来的FirstName,SecondName,LastName?

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