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为什么下面这个函数中的值是对象呢

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2016-06-13 12:09:45731browse

为啥下面这个函数中的值是对象呢

public function -run($type){<br />    $type->version();<br />    $type->work();<br />}

函数的值怎么能是函数呢，函数的值到底是怎么规定的
------解决思路----------------------
函数的参数可以是任何数据（当然你可以自己限定）
在你示例的代码中 $type 就是一个对象

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