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PHP将DateTime对象转化为友好时间显示的实现代码

WBOY
WBOYOriginal
2016-06-13 12:04:57760browse

复制代码 代码如下:


/**
* 友好日期时间
*
* @param DateTime $datetime 日期时间
* @param int $size 精确到位数
* @throws \InvalidArgumentException
* @return string
*/
function friendly_date($datetime, $size=1)
{
if (is_int($datetime)) {
$datetime = new \DateTime($datetime);
}
if (!($datetime instanceof \DateTime)) {
throw new \InvalidArgumentException('invalid "DateTime" object');
}
$now = new \DateTime();
$interval = $now->diff($datetime);
$intervalData = array(
$interval->y, $interval->m, $interval->d,
$interval->h, $interval->i, $interval->s,
);
$intervalFormat = array('年', '个月', '天', '小时', '分种', '秒');
foreach($intervalData as $index=>$value) {
if ($value) {
$intervalData[$index] = $value . $intervalFormat[$index];
} else {
unset($intervalData[$index]);
unset($intervalFormat[$index]);
}
}
return implode('', array_slice($intervalData, 0, $size));
}

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