把几个数字拆分保存的算法问题
假如有五个数字:1,2,3,4,5,要保存到数组中,结果如下:
数组1:2,3,4,5
数组2:1,3,5
数组3:1,2,3,4,5
数组4:1,2,4
一共有4个数组,我的目的是把这5个数字在这四个数组中每个数字都出现3次,这样有一个数组不存在了,从其它数组也能把所有数字取出来。
我不需要代码,只要有思路就行,谢谢各位达人。
------解决方案--------------------
想了一下,你这还不是 raid5.你的这个方案的冗余度要大的多
象这样组织数据的话,可以在丢失任意两组数据的情况下,读出数据。
不过组织方式与你的略有不同
- PHP code
$ar = array( array(0,2,3,4,5), array(1,0,3,0,5), array(1,2,3,4,5), array(1,2,0,4,0),);unset($ar[3]);unset($ar[1]);for($i=0; $i<font color="#e78608">------解决方案--------------------</font><br>
- PHP code
<?phpfunction split2Array($n, $repeat = 3){ $result = array(); for($i = 0; $i < $n; $i++) { for($j = 0; $j < $repeat; $j++) { $result[($i + $j) % ($repeat + 1)][$i] = $i + 1; } } return $result;}print_r(split2Array(7, 4));?><div class="clear"> </div>

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