如何在PHP函数中使用另外一个函数返回的数组
示例代码如下,最后在f2中得不到f1返回的数组,print_r($b);显示为空
- PHP code
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--><?PHPfunction f1(){ $a=array("1","2","3"); /* 定义一个数组 */ return $a;}function f2(){ $b = f1(); print_r($b);}f2();?>
------解决方案--------------------
能得到。不知道你运行在什么环境中?
------解决方案--------------------
- PHP code
<?phpfunction f1(){ $a=array("1","2","3"); /* 定义一个数组 */ return $a;}function f2(){ $b = f1(); #如果在类中,就需要$this->f1() print_r($b);}f2();#Array ( [0] => 1 [1] => 2 [2] => 3 )?><br><font color="#e78608">------解决方案--------------------</font><br>没有关系<br>都能得到结果<br><font color="#e78608">------解决方案--------------------</font><br>反正我的是能得到<div class="clear"> </div>

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