


In Go: Why do function parameters and return values often use []*User instead of []User?
Detailed explanation of Go language slice: In-depth understanding []*User
Go slicing is powerful, efficient and flexible, and is ideal for many programming tasks. But the slice type []*User
often confuses developers. This article will explore the meaning and usage scenarios of []*User
in depth, explaining the reasons why it frequently appears in function parameters and return values.
Why is Go slicing a reference type, but []*User
is commonly used instead of []User
in function parameters and return values?
The key lies in the type of slice elements. var users []*User
, whose elements are pointers to the User
structure. Each element is a pointer pointing to the User
structure instance on the heap. Modifying the slice element will directly modify the corresponding User
structure.
The slice declared by var users []User
is the User
structure itself (value type). The slice stores a copy of the User
structure. Modifying the slice element will only modify the copy and will not affect the original User
structure.
Therefore, if the function needs to modify the User
structure pointed to by the external variable, you must use []*User
. []*User
ensures that the modifications to slice elements inside the function will be reflected outside the function, while []User
can only modify the copy, and external variables are not affected. When modifying multiple User
structures, []*User
is more efficient, avoiding performance losses of value copying.
This difference is equally important in function parameters and return value transfer. Using []*User
as a parameter, the function can directly operate the incoming User
structure, and the modification results will be reflected outside the function. Using []User
as a parameter, the function can only modify the copy and cannot change the external User
structure. Therefore, it is crucial to choose the right slice type and depends on actual needs.
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