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How to Deserialize JSON into C# Dynamic Objects?

Mary-Kate Olsen
Mary-Kate OlsenOriginal
2025-02-03 01:56:13194browse

How to Deserialize JSON into C# Dynamic Objects?

In the C#, JSON's back serving into a dynamic object

In the .NET programming,

is usually used to serve serialized JSON content. However, creating a custom class for each JSON object may be cumbersome. In order to simplify this process, JSON can be serialized into a C#dynamic type.

DataContractJsonSerializer Use json.net

JSON.NET provides a convenient way to sequence JSON's derivatives into dynamic objects:

This code turns JSON back order into a dynamic object named "Stuff". You can then use point representation to directly access its attributes.

<code class="language-csharp">dynamic stuff = JsonConvert.DeserializeObject("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }");

string name = stuff.Name;
string address = stuff.Address.City;</code>
Use newtonsoft.json.linq

newtonsoft.json.linq also provides a way to analyze JSON as dynamic objects:

This code uses to create a

from JSON, and then you can access it as a dynamic object.

<code class="language-csharp">dynamic stuff = JObject.Parse("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }");

string name = stuff.Name;
string address = stuff.Address.City;</code>
More resources

JObject.Parse JObject For more information about this topic, please refer to the following documents:

json.net uses a dynamic object to query json

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