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HomeBackend DevelopmentPython TutorialSolving the Weekly Challenge Task Step by Step in Python

Solving the Weekly Challenge  Task Step by Step in Python

1. Introduction

The Weekly Challenge, organized by Mohammad S. Anwar, is a friendly competition in which developers compete by solving a pair of tasks. It encourages participation from developers of all languages and levels through learning, sharing, and having fun.

Task 2: Step by Step from The Weekly Challenge requires developers to find a starting value that makes a step-by-step sum never smaller than one.

In this post I discuss, and present my Python language solution to, Task 2: Step by Step, and wrap with a brief conclusion.

2. Task 2: Step by Step

You are given an array of integers, @ints.

Write a script to find the minimum positive start value such that the step by step sum is never less than one.

The Weekly Challenge 302, Task 2: Step by Step

Examples 1 - 3 present the expected outputs from given inputs.

Example 1

Input: @ints = (-3, 2, -3, 4, 2)
Output: 5

For start value 5.

5 + (-3) = 2
2 + (+2) = 4
4 + (-3) = 1
1 + (+4) = 5
5 + (+2) = 7

Example 2

Input: @ints = (1, 2)
Output: 1

Example 3

Input: @ints = (1, -2, -3)
Output: 5

3. My solution to Task 2

def return_min_start(ints: list[int]) -> int | None:
    for start_value in range(1, 1000000):
        step_sum = start_value + ints[0]
        if step_sum = 1:
            return start_value
    return None

My solution uses for loops and if statements to incrementally search for the start_value that matches the task requirements:

  • I incrementally search for starting values within the range of [1, 1000000). For each start_value:
    • I calculate the step-by-step sum (step_sum) of start_value and ints[0]. If step_sum is less than one, then I start over with the next possible start_value.
    • I calculate step_sum for the remaining elements of ints. If step_sum is less than one for any element, then I start over with the next possible start_value.
    • If the final step_sum for start_value is greater than one, then I return start_value.
  • If I do not find a start_value within the range of [1, 1000000), then I return None.

4. Conclusion

In this post I discussed Task 2: Step by Step and I presented my solution.

Learn more about the latest and past challenges at The Weekly Challenge website:
https://theweeklychallenge.org/

Learn more about competing at The Weekly Challenge FAQ:
https://theweeklychallenge.org/faq/

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