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You're seeking a method to generate all possible 2^N combinations from a list of 15 elements, accommodating combinations of any length while maintaining the original order. While your approach involving binary representation is a viable option, let's explore a more comprehensive solution.
Instead of relying on the binary representation, consider employing the itertools.combinations() function from the Python standard library. This function generates a sequence of all combinations of a given length from a given iterable. By varying the length parameter, you can obtain combinations of any desired size.
The following Python code demonstrates this approach:
import itertools stuff = [1, 2, 3] # Loop through all possible lengths for L in range(len(stuff) + 1): # Generate combinations of length L for subset in itertools.combinations(stuff, L): print(subset)
This code will generate all 32,768 possible combinations of the elements in the stuff list, regardless of their length.
Alternatively, for a more streamlined solution, you can use the chain() and combinations() functions to generate a single sequence containing all combinations of all possible lengths:
import itertools from itertools import chain, combinations def all_subsets(ss): return chain(*map(lambda x: combinations(ss, x), range(0, len(ss)+1))) for subset in all_subsets(stuff): print(subset)
This code achieves the same result but in a more concise and arguably elegant manner.
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