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HomeBackend DevelopmentGolangWhy Does Re-slicing a Go Slice Not Always Reduce Its Capacity?

Why Does Re-slicing a Go Slice Not Always Reduce Its Capacity?

Re-Slicing Slices in Golang

In Go, slices provide a flexible way to manage collections of elements. While creating and accessing slices is straightforward, understanding the behavior of re-slicing them can be tricky. Let's explore a code snippet that illustrates this concept:

package main

import "fmt"

func main() {
    a := make([]int, 5)
    printSlice("a", a)
    b := make([]int, 0, 5)
    printSlice("b", b)
    c := b[:2]
    printSlice("c", c)
    d := c[2:5]
    printSlice("d", d)
}

func printSlice(s string, x []int) {
    fmt.Printf("%s len=%d cap=%d %v\n",
        s, len(x), cap(x), x)
}

This code creates a slice a with a length of 5 and a capacity of 5, followed by two slices b and c with lengths and capacities of 0 and 2 respectively. Slice d is then created as a re-slice of c with a start index of 2 and an end index of 5.

The confusing part arises when observing the output:

a len=5 cap=5 [0 0 0 0 0]
b len=0 cap=5 []
c len=2 cap=5 [0 0] //why the capacity of c not 2 but 5 instead
d len=3 cap=3 [0 0 0]

Understanding Re-Slicing

When re-slicing a slice, it's important to remember that slices are not copies of their underlying arrays. Instead, they are windows that reference a portion of the array.

  • In the case of slice c, it's created as a slice of the first two elements of slice b. Since b has a capacity of 5, slice c can be extended to include the remaining three elements. This is why its capacity remains at 5.
  • Slice d is then created as a re-slice of c with a start index of 2. This means that d references the elements of b in the range of [2, 5). Since there are only three elements left in this range, the length of d is 3, and its capacity is 3 (since it's a part of a larger slice with a total capacity of 5).

Further Clarification

The following code exemplifies the close relationship between re-sliced slices:

func main() {
    b := make([]int, 0, 5)
    c := b[:2]
    d := c[1:5] // this is equivalent to d := b[1:5]
    d[0] = 1
    printSlice("c", c)
    printSlice("d", d)
}

Output:

c len=2 cap=5 [0 1] // modifying d has modified c
d len=4 cap=4 [1 0 0 0] 

This demonstrates that modifying the elements of slice d directly affects the elements of slice c, confirming that both slices share the same underlying data.

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