Home >Database >Mysql Tutorial >Does MySQLi's `prepare()` Return Value Indicate Only Preparation Errors or Also Execution Errors?
When utilizing MySQLi to execute SQL queries, it's crucial to handle error reporting effectively. In the provided code snippet, where the return value of the stmt_init() method is used to detect errors during SQL preparation, a lingering doubt arises:
Does the prepare statement's return value solely indicate errors in SQL statement preparation or also execution errors?
To elucidate this, consider the following alternative error handling approach:
if($stmt_test->execute()) $errorflag=true;
This code checks for errors during statement execution. However, it's not necessary to implement this additional check because the return value of the prepare() method encompasses both preparation and execution errors.
To ensure comprehensive error reporting, it's advisable to add the following line to your connection code:
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
This enables the reporting of all mysqli errors. As a result, you can eliminate the need to check return values and write statements directly, as shown in the following example:
$stmt = $mysqli->prepare("INSERT INTO testtable VALUES (?,?,?)"); $stmt->bind_param('iii', $x, $y, $z); $stmt->execute();
In the event of an error at any stage, a PHP exception will be thrown. This exception can be handled or reported like any other PHP error. By configuring PHP error reporting appropriately, you can ensure that errors are displayed on-screen during development and logged on the production server.
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