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In Go, extending existing types defined in external packages is not directly supported. However, there are workarounds to achieve a similar result.
Let's consider the example provided in the question:
package util import( "net/http" "github.com/0xor1/gorillaseed/src/server/lib/mux" ) func (r *mux.Route) Subroute(tpl string, h http.Handler) *mux.Route{ return r.PathPrefix("/" + tpl).Subrouter().PathPrefix("/").Handler(h) } func (r *mux.Router) Subroute(tpl string, h http.Handler) *mux.Route{ return r.PathPrefix("/" + tpl).Subrouter().PathPrefix("/").Handler(h) }
When attempting to compile this code, one encounters the error: "Cannot define new methods on non-local type mux.Router". This is because Go does not allow direct extension of types from external packages.
Workaround 1: Define a Wrapper Type
One workaround is to define a wrapper struct that embeds the original type and provides the desired methods. For example:
type MyRoute struct { *mux.Route } func (r *MyRoute) Subroute(tpl string, h http.Handler) *mux.Route { return r.PathPrefix("/" + tpl).Subrouter().PathPrefix("/").Handler(h) } type MyRouter struct { *mux.Router } func (r *MyRouter) Subroute(tpl string, h http.Handler) *mux.Route { return r.PathPrefix("/" + tpl).Subrouter().PathPrefix("/").Handler(h) }
Workaround 2: Type Assertion
Another option is to use type assertion to convert the original type to an interface{} and then to a custom type that provides the desired methods. For example:
func (r interface{}) Subroute(tpl string, h http.Handler) *mux.Route { switch v := r.(type) { case *mux.Route: return v.PathPrefix("/" + tpl).Subrouter().PathPrefix("/").Handler(h) case *mux.Router: return v.PathPrefix("/" + tpl).Subrouter().PathPrefix("/").Handler(h) default: panic("unreachable") } }
Note: These workarounds may introduce additional complexity and should be used carefully. If possible, it is best to avoid modifying external types and instead define your own types that wrap or extend the functionality you need.
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