How to Handle File Uploads in a Golang net/http Server?

How to Receive an Uploaded File Using a Golang net/http Server

When attempting to implement a simple file upload endpoint in Golang using Mux and net/http, retrieving the file data from the request body can pose a challenge. The following solution addresses this issue:

import (
    "bytes"
    "fmt"
    "io"
    "net/http"
    "strings"
)

func ReceiveFile(w http.ResponseWriter, r *http.Request) {
    r.ParseMultipartForm(32 << 20) // limit your max input length!
    var buf bytes.Buffer
    file, header, err := r.FormFile("file") // replace "file" with the expected form field name
    if err != nil {
        panic(err)
    }
    defer file.Close()
    name := strings.Split(header.Filename, ".")
    fmt.Printf("File name %s\n", name[0])
    io.Copy(&buf, file)
    contents := buf.String()
    fmt.Println(contents)
    buf.Reset()
    return
}

This function:

• Parses the request's multipart form.
• Retrieves the uploaded file from the provided field name (replace "file" with your actual field name).
• Reads the file's contents into a buffer.
• Prints the file's name to the console.
• Converts the buffer's contents to a string.
• Prints the file's contents to the console.
• Resets the buffer for potential reuse.

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