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In Python 3, performing regex-based replacements on a large number of strings can be a time-consuming process. This article explores two potential methods to enhance the efficiency of such operations for scenarios where replacements need to occur only at word boundaries.
Using the str.replace method can potentially offer improved performance over re.sub. To ensure replacements are confined to word boundaries, utilize the b metacharacter within the replace method. For example:
import string # Create a list of common English stop words stop_words = set(line.strip() for line in open('stop_words.txt')) # Define a function for replacing stop words def replace_stop_words(text): # Generate pattern by escaping each stop word with \b metacharacter pattern = r'\b' + string.join(['\b%s\b' % word for word in stop_words]) + r'\b' # Perform the replacement using str.replace return text.replace(pattern, '')
Another approach to accelerate the replacement process involves utilizing a trie, which is a tree-like data structure created from the banned words list. The trie's structure allows for efficient matching and can result in substantial performance gains.
import trie # Initialize the trie trie = trie.Trie() # Add banned words to the trie for word in banned_words: trie.add(word)
# Obtain the regular expression banned_words_pattern = r"\b" + trie.pattern() + r"\b"
# Perform the replacement using re.sub for sentence in sentences: sentence = sentence.replace(banned_words_pattern, '')
Both methods offer potential performance advantages. The choice depends on specific requirements and the size of the banned words list. For a relatively small list, the word boundary replacements approach using str.replace may suffice. However, for larger banned words lists, the trie-based method can lead to significantly faster execution times.
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