How to Sort a Go Struct by its `time.Time` Field?

Sorting a Struct by Time.Time Field in Go

When attempting to sort a struct by its member of type time.Time, users may encounter unexpected results. This issue arises because the default sort package lacks functionality for sorting time.Time values.

Problem Description:

The provided struct, reviews_data, has a member called date of type time.Time. Users have defined a custom slice type, timeSlice, implementing the Len, Less, and Swap methods for sorting the slice. They attempt to map a map of reviews_data to timeSlice, sort the slice, and expect the map to be sorted by its date values. However, the sorting does not occur as expected.

Solution:

For Go versions 1.8 and above, the issue can be resolved by using the sort.Slice function instead of sort.Sort. The new syntax for sorting the slice by the date field would be:

sort.Slice(timeSlice, func(i, j int) bool {
    return timeSlice[i].date.Before(timeSlice[j].date)
})

The sort.Slice function takes the slice to be sorted and a closure defining the comparison function. In this case, the closure compares the date values of two elements in the slice.

Explanation:

Prior to Go 1.8, the sort.Sort function could only be used with types that implemented the Sorter interface. In Go 1.8 and above, sort.Slice was introduced, allowing users to sort slices using a closure without requiring the implementation of a custom Sorter type.

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