How to Efficiently Convert Hexadecimal Strings to Float32 Values in Go?

Converting Hexadecimal Strings to Float Values

When trying to convert hexadecimal strings (e.g., "0xC40C5253") to floating-point values using strconv.ParseFloat proves unsuccessful, alternative methods need to be explored.

One approach involves utilizing the strconv.ParseUint() function to parse the bytes from the hex representation into an unsigned 32-bit integer (uint32). This is necessary because float32, commonly used to represent a float value with a 4-byte length, requires bytes to be interpreted as such.

Using the unsafe package, the bytes can be reinterpreted as a float32 value by creating a pointer to the uint32 variable and assigning it to a float32 variable.

An alternative approach suggested by JimB is to use the math package's built-in function, math.Float32frombits(). This function directly converts an unsigned 32-bit integer to a float32 value, eliminating the need for unsafe pointer operations.

Here is an updated code snippet that demonstrates the process:

package main

import (
    "fmt"
    "strconv"
    "unsafe"
)

func main() {
    s := "C40C5253"
    n, err := strconv.ParseUint(s, 16, 32)
    if err != nil {
        panic(err)
    }
    n2 := uint32(n)
    funsafe := *(*float32)(unsafe.Pointer(&n2))
    fmt.Println(funsafe)
    fmath := math.Float32frombits(n2)
    fmt.Println(fmath)
}

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