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Updating a Nested Dictionary of Varying Depth
To seamlessly update a nested dictionary (dictionary1) with the contents of another nested dictionary (update) while preserving specific key-value pairs, it is necessary to employ a recursive solution that considers the varying depths of the dictionaries.
Consider the following example scenario:
Before Update:
dictionary1 = { "level1": { "level2": {"levelA": 0, "levelB": 1} } } update = { "level1": { "level2": {"levelB": 10} } }
Using the standard update method would overwrite the existing "level2" values in dictionary1, resulting in:
dictionary1.update(update) print(dictionary1)
{ "level1": { "level2": {"levelB": 10} # "levelA" is lost } }
Recursive Solution:
To address this preservation requirement, the following Python code provides a recursive solution:
import copy def update_dictionary(d, u): for k, v in u.items(): if isinstance(v, dict): # If the value is a dictionary, recursively update d[k] = update_dictionary(d.get(k, {}), v) else: # If the value is not a dictionary, simply update d[k] = copy.deepcopy(v) return d
This solution creates a deep copy of the original dictionary1 to prevent in-place updates. It then iterates through the update dictionary (u) and recursively updates the corresponding values in d. If the value is a dictionary, it continues the recursion; otherwise, it updates the value directly.
Usage:
Applying this solution to the earlier example:
result = update_dictionary(dictionary1, update) print(result)
Result:
{ "level1": { "level2": {"levelA": 0, "levelB": 10} # "levelA" preserved } }
This solution effectively updates the "levelB" value while preserving the "levelA" value in the original dictionary. It handles nested dictionaries of varying depths, ensuring that specific key-value pairs are preserved during the update process.
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