How to Fix \'Value of type java.lang.String cannot be converted to JSONObject\' Error in Android?

Troubleshooting a "Value u003cbru003e of type java.lang.String cannot be converted to JSONObject" Error

In your Android application, you're encountering an error related to JSON parsing. Specifically, you're seeing the following exception:

<code class="java">org.json.JSONException: Value 

<br of type java.lang.string cannot be converted to jsonobject><p>This error indicates that you're attempting to parse a non-JSON string as JSON. Here's how you can troubleshoot this issue:</p>
<ol>
<li>
<strong>Check your server response:</strong> The request to your PHP script may be failing or returning a non-JSON response. Add a Log.i("tagconvertstr", "[" result "]"); line before the JSONObject call in your Android code to print out the actual response.</li>
<li>
<strong>Debug using a break point:</strong> If you're using Eclipse, you can set a break point in your code and step through it to see what's happening. This will allow you to inspect the values and identify the cause of the error.</li>
<li>
<strong>Revisit your PHP script:</strong> Ensure that your PHP script is properly handling the data and returning a valid JSON string. Verify that the data is being received correctly on the Android side.</li>
</ol>
<p>Here's an example of how you can troubleshoot the error:</p>
<pre class="brush:php;toolbar:false"><code class="java">Log.i("tagconvertstr", "["+result+"]");
try {
    JSONObject jObj = new JSONObject(result);

    donnees = jObj.getString("message");
} catch (JSONException e) {
    Log.i("tagjsonexp", "" + e.toString());
} catch (ParseException e) {
    Log.i("tagjsonpars", "" + e.toString());
}</code>

By adding the Log.i("tagconvertstr", "[" result "]"); line, you can inspect the value of result and identify the cause of the error. Additionally, stepping through your code will help you pinpoint the issue and resolve it.

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