Home >Backend Development >Golang >How to Perform Type Assertion with Function Parameters in Go?
In an attempt to perform type assertion, you seek to pass a specific type into a function. Specifically, you aim to achieve a function declaration that enables you to assertively match against a provided type, as illustrated in the hypothetical function below:
// Note: Type isn't a valid type to use in Go func myfunction(mystring string, mytype Type) { ... someInterface := translate(mystring) object, ok := someInterface.(mytype) ... // Do other stuff }
To successfully implement type assertion within myfunction, you should modify the function declaration to accept an interface{} parameter for mytype. Here's how you can achieve this:
func myfunction(v interface{}, mytype interface{}) bool { return reflect.TypeOf(v) == reflect.TypeOf(mytype) }
This approach utilizes the reflect package to compare the type of the v parameter with the provided mytype interface. It returns a boolean value indicating whether the types match or not.
Here's an example that demonstrates how you can utilize this function:
package main import ( "fmt" "reflect" ) func main() { assertNoMatch := myfunction("hello world", map[string]string{}) fmt.Printf("%+v\n", assertNoMatch) assertMatch := myfunction("hello world", "stringSample") fmt.Printf("%+v\n", assertMatch) }
In this example, the myfunction correctly determines whether the provided value matches the specified type and returns a boolean accordingly.
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