How to Check if a C String Ends with a Specific String?

Finding String Endings with C

Determining whether a string concludes with another sequence of characters is a common task in programming. In C , this functionality can be easily achieved using the std::string::compare method.

Solution:

To verify if the ending string exists at the end of the full string, we need to compare the last n characters of the fullString against the ending string. Here's a function that performs this task:

<code class="cpp">bool hasEnding(const std::string& fullString, const std::string& ending) {
    if (fullString.length() >= ending.length()) {
        return (0 == fullString.compare(fullString.length() - ending.length(), ending.length(), ending));
    } else {
        return false;
    }
}</code>

Explanation:

• Check if the fullString is long enough to contain the ending.
• If so, compare the last n characters of the fullString (where n is the length of the ending) with the ending string using compare.
• If the comparison returns 0, the strings are identical, and the function returns true. Otherwise, it returns false.

Example Usage:

In the provided main function, we test out the hasEnding function with various strings and an ending string:

<code class="cpp">int main() {
    // Test strings
    std::string test1 = "binary";
    std::string test2 = "unary";
    std::string test3 = "tertiary";
    std::string test4 = "ry";

    // Ending string
    std::string ending = "nary";

    // Print results
    std::cout << hasEnding(test1, ending) << std::endl;
    std::cout << hasEnding(test2, ending) << std::endl;
    std::cout << hasEnding(test3, ending) << std::endl;
    std::cout << hasEnding(test4, ending) << std::endl;

    return 0;
}</code>

Output:

true
false
false
true

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