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In C++ template programming, when type inference fails, the following method can be used to solve the problem: explicitly specify template parameters. For example: func
Troubleshooting in Template Programming in C++: Type Inference Failure
Problem:
When using C++ templates, you may encounter failures during type inference, resulting in compilation errors. For example:
template<typename T> void func(T t) { // ... } int main() { func<int>(); // 类型推断失败 }
Solution:
In order to solve the type inference failure, you can use explicit template parameterization and manually specify the type parameters:
template<typename T> void func(T t) { // ... } int main() { func<int>(10); // 显式指定类型参数 }
Practical case:
Consider the following program that uses an Array
template to create an array of any type:
template <typename T> struct Array { T* data; size_t size; Array(size_t size) : data(new T[size]), size(size) {} ~Array() { delete[] data; } T& operator[](size_t index) { return data[index]; } }; int main() { Array<int> arr(10); for (size_t i = 0; i < arr.size; ++i) { arr[i] = i * i; } for (size_t i = 0; i < arr.size; ++i) { std::cout << arr[i] << " "; } std::cout << std::endl; return 0; }
This program demonstrates the type -safe behavior of C++ templates. The Array
template is instantiated with the int
type, creating an array of integers. The elements of the arrays can be accessed and modified using the operator[]
method. The program prints the contents of the array, which are the squares of the integers from 0 to 9.
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