How to parse CSV files using regular expressions in Go?

How to parse CSV files using regular expressions in Go? 1. Import the regexp library. 2. Use regexp.MustCompile to create a regular expression that matches the CSV row fields. 3. Use the regexp.Split function to split the CSV row into an array of strings. 4. A practical case shows how to use regular expressions to parse CSV files containing personnel data.

How to use regular expressions to parse CSV files in Go

Regular expressions (regex) are a powerful tool. For matching and processing text. In Go, we can use the regexp package to process CSV files.

1. Import library

import (
    "fmt"
    "regexp"
)

2. Match CSV rows

Useregexp.MustCompile Create a regular expression pattern that matches fields in a CSV row:

re := regexp.MustCompile(`^([^,]*),([^,]*),(.+)$`)

This pattern matches each field with three capturing groups.

3. Parse CSV rows

Use the regexp.Split function to split the CSV row into an array of strings:

line := "John,Doe,jdoe@example.com"
fields := re.Split(line, -1)

fields The array now contains three elements: name, last name, and email address.

4. Practical case

Let us use regular expressions to parse a CSV file containing personnel data:

package main

import (
    "fmt"
    "io/ioutil"
    "regexp"
)

func main() {
    // 读取 CSV 文件
    data, err := ioutil.ReadFile("people.csv")
    if err != nil {
        fmt.Println(err)
        return
    }

    // 使用正则表达式解析 CSV 行
    re := regexp.MustCompile(`^([^,]*),([^,]*),(.+)$`)
    lines := strings.Split(string(data), "\n")
    for _, line := range lines {
        fields := re.Split(line, -1)
        if len(fields) != 4 {
            fmt.Println("无效的行：", line)
            continue
        }

        // 打印个人信息
        fmt.Printf("%s %s (%s)\n", fields[1], fields[2], fields[3])
    }
}

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