php实现随机显示图片方法汇总
本文分享一个php实现的随机显示图片的函数,可以将指定文件夹中存放的图片随机地显示出来。有兴趣的朋友研究下吧。
php通过rand()函数产生随机数,这个函数可以产生一个指定范围的数字
这段代码通过产生的随机数,随机选择图片
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srand( microtime() * 1000000 ); $num = rand( 1, 4 );
switch( $num ) { case 1: $image_file = "/home/images/alfa.jpg"; break; case 2: $image_file = "/home/images/ferrari.jpg"; break; case 3: $image_file = "/home/images/jaguar.jpg"; break; case 4: $image_file = "/home/images/porsche.jpg"; break; } echo "Random Image : ?> |
方法二:
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$handle = opendir('./'); //当前目录 while (false !== ($file = readdir($handle))) { //遍历该php教程文件所在目录 list($filesname,$kzm)=explode(".",$file);//获取扩展名 if ($kzm=="gif" or $kzm=="jpg") { //文件过滤 if (!is_dir('./'.$file)) { //文件夹过滤 $array[]=$file;//把符合条件的文件名存入数组 } } } $suiji=array_rand($array); //使用array_rand函数从数组中随机抽出一个单元 ?> |
方法三:
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/********************************************** * Filename : img.php * Author : freemouse * Usage: * * ***********************************************/ if($_GET['folder']){ $folder=$_GET['folder']; }else{ $folder='/images/'; } //存放图片文件的位置 $path = $_SERVER['DOCUMENT_ROOT']."/".$folder; $files=array(); if ($handle=opendir("$path")) { while(false !== ($file = readdir($handle))) { if ($file != "." && $file != "..") { if(substr($file,-3)=='gif' || substr($file,-3)=='jpg') $files[count($files)] = $file; } } } closedir($handle); $random=rand(0,count($files)-1); if(substr($files[$random],-3)=='gif') header("Content-type: image/gif"); elseif(substr($files[$random],-3)=='jpg') header("Content-type: image/jpeg"); readfile("$path/$files[$random]"); ?> |
以上所述就是本文的全部内容了,希望大家能够喜欢。

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