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javascript - 如何匹配"height:12px;width:56px;background:#fff;"中间的"width:56px;"?

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2016-06-06 20:38:30992browse

其中":56px"是未知的，我结果希望replace之后是这样的height:12px;background:#fff;，下面是我写的，会把width后面的全部删掉的

<code>var str = "height:12px;width:56px;background:#fff;";
str.replace(RegExp('width.*;'),'');
//=>height:12px;
</code>

回复内容：

其中":56px"是未知的，我结果希望replace之后是这样的height:12px;background:#fff;，下面是我写的，会把width后面的全部删掉的

<code>var str = "height:12px;width:56px;background:#fff;";
str.replace(RegExp('width.*;'),'');
//=>height:12px;
</code>

str.replace(RegExp('width[^;]*;'),'');

str.replace(RegExp('width:\\w*;'), '');

<code>var str = "height:12px;width:56px;background:#fff;";
str.replace(RegExp('width.*?;'),'');
</code>
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