本人刚开始接触服务器所以不是很懂
公司的服务器的版本是
<code>html</code><code>Linux version 2.6.32-431.20.3.el6.x86_64 (mockbuild@c6b9.bsys.dev.centos.org) (gcc version 4.4.7 20120313 (Red Hat 4.4.7-4) (GCC) ) #1 SMP Thu Jun 19 21:14:45 UTC 2014 </code>
google了一下更新PHP的方法用了
<code>yum install php54w </code>
但是最后提示的错误是
<code>Error: php54w-common conflicts with php-common-5.3.3-40.el6_6.x86_64 You could try using --skip-broken to work around the problem You could try running: rpm -Va --nofiles --nodigest </code>
按照提示执行了--skip-broken等 没有起作用
又google了一下发现别人说用
<code>yum remove php-common </code>
但是google不到php-common的作用 所以不敢就这么移除了
问下各位
用
1.yum install php54w
可以安装到php5.4吗
2.有人用过remove php-common 解决这个问题吗
3.php-common的作用是什么
4.升级php5.4之后对mysql的版本有要求吗?
回复内容:
本人刚开始接触服务器所以不是很懂
公司的服务器的版本是
<code>html</code><code>Linux version 2.6.32-431.20.3.el6.x86_64 (mockbuild@c6b9.bsys.dev.centos.org) (gcc version 4.4.7 20120313 (Red Hat 4.4.7-4) (GCC) ) #1 SMP Thu Jun 19 21:14:45 UTC 2014 </code>
google了一下更新PHP的方法用了
<code>yum install php54w </code>
但是最后提示的错误是
<code>Error: php54w-common conflicts with php-common-5.3.3-40.el6_6.x86_64 You could try using --skip-broken to work around the problem You could try running: rpm -Va --nofiles --nodigest </code>
按照提示执行了--skip-broken等 没有起作用
又google了一下发现别人说用
<code>yum remove php-common </code>
但是google不到php-common的作用 所以不敢就这么移除了
问下各位
用
1.yum install php54w
可以安装到php5.4吗
2.有人用过remove php-common 解决这个问题吗
3.php-common的作用是什么
4.升级php5.4之后对mysql的版本有要求吗?
问题解决
<code><br>yum install yum-plugin-replace yum replace php-common --replace-with=php54w-common </code>

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The server session failure can be solved through the following steps: 1. Check the server configuration to ensure that the session is set correctly. 2. Verify client cookies, confirm that the browser supports it and send it correctly. 3. Check session storage services, such as Redis, to ensure that they are running normally. 4. Review the application code to ensure the correct session logic. Through these steps, conversation problems can be effectively diagnosed and repaired and user experience can be improved.

session_start()iscrucialinPHPformanagingusersessions.1)Itinitiatesanewsessionifnoneexists,2)resumesanexistingsession,and3)setsasessioncookieforcontinuityacrossrequests,enablingapplicationslikeuserauthenticationandpersonalizedcontent.

Setting the httponly flag is crucial for session cookies because it can effectively prevent XSS attacks and protect user session information. Specifically, 1) the httponly flag prevents JavaScript from accessing cookies, 2) the flag can be set through setcookies and make_response in PHP and Flask, 3) Although it cannot be prevented from all attacks, it should be part of the overall security policy.

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PHPsessionscanstorestrings,numbers,arrays,andobjects.1.Strings:textdatalikeusernames.2.Numbers:integersorfloatsforcounters.3.Arrays:listslikeshoppingcarts.4.Objects:complexstructuresthatareserialized.

TostartaPHPsession,usesession_start()atthescript'sbeginning.1)Placeitbeforeanyoutputtosetthesessioncookie.2)Usesessionsforuserdatalikeloginstatusorshoppingcarts.3)RegeneratesessionIDstopreventfixationattacks.4)Considerusingadatabaseforsessionstoragei

Session regeneration refers to generating a new session ID and invalidating the old ID when the user performs sensitive operations in case of session fixed attacks. The implementation steps include: 1. Detect sensitive operations, 2. Generate new session ID, 3. Destroy old session ID, 4. Update user-side session information.


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