首页  >  文章  >  web前端  >  jquery简单实现图片切换效果的方法_jquery

jquery简单实现图片切换效果的方法_jquery

WBOY
WBOY原创
2016-05-16 15:59:451084浏览

本文实例讲述了jquery简单实现图片切换效果的方法。分享给大家供大家参考。具体实现方法如下:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" 
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />
<title>无标题文档</title>
<style type="text/css">
#slider{
 position:relative;
 overflow:hidden;
 margin:20px auto;
 height:240px;
 width:740px;
 padding:5px;
 border:2px solid #cdcdcd;
}
#show{
 position:relative;
 height:240px; 
 width:740px;
}
#show .img{
 width:740px;
 height:240px;
 margin-bottom:5px;
}
#num{
 position:absolute;
 right:5px;
 top:220px;
}
#num span{
 float:left;
 display:block;
 text-align:center;
 width:20px;
 height:20px;
 line-height:20px;
 margin:2px;
 font-family:Arial, Helvetica, sans-serif;
 font-size:14px;
 font-weight:blod;
 background:#f2f2f2;
 border:1px solid #D78918;
 color:#D78918;
}
#num .current{
 color: #fff;
 width:21px;
 height:21px;
 line-height:21px;
 font-size: 16px;
 border:0px;
 margin:0px 1px;
 background-color: #FF7300;
}
</style>
<script src="js/jquery-1.3.1.js" type="text/javascript"></script>
<script type="text/javascript">
<!--
$(function(){
 var count=1;
 setInterval(function(){
 count=count==5&#63;0:count;
 var top=-count*(240+5);
 count++;
 $("#show").animate({top:top},600);
 $("#num").find("span").eq(count-1).addClass("current").siblings().removeClass("current");
 },2000);
})
-->
</script>
</head>
<body>
<div id="slider">
 <div id="show">
   <div class="img" style="background:red;"></div>
   <div class="img" style="background:blue"></div>
   <div class="img" style="background:gold"></div>
   <div class="img" style="background:yellow"></div>
   <div class="img" style="background:green"></div>
  </div>
  <div id="num">
  <span class="current">1</span>
  <span>2</span>
  <span>3</span>
  <span>4</span>
  <span>5</span>
  </div>
</div>
</body>
</html>

希望本文所述对大家的jQuery程序设计有所帮助。

声明:
本文内容由网友自发贡献,版权归原作者所有,本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容,请联系admin@php.cn