实现双向链表

假设理解 Big O 表示法。 JavaScript 中有示例。资料参考 Gayle Laakmann McDowell 的《Cracking the Coding Interview》

理解双向链表

双向链表与单链表非常相似，除了节点的结构和添加/删除节点的方式不同。

节点结构

双向链表中的节点包含

prev 指针、next 指针和 value。 prev 指针指向前一个节点，next 指针指向下一个节点。本质上，这个列表在每个节点都是双向的。

添加节点

要在特定索引处插入新节点（newNode）：

1. 将当前位于插入索引处的节点存储在临时变量 nextNode 中。

2. 更新前一个节点和新节点的连接：
   将前一个节点的next指针设置为newNode。
   将newNode的prev指针设置为前一个节点。
3. 将新节点连接到下一个节点：
   将newNode的next指针设置为nextNode。
   将 nextNode 的 prev 指针设置为 newNode。

删除节点

要删除特定索引处的节点：

更新前一个节点的下一个指针：
1. 设置为指向被移除后的节点。
更新下一个节点的 prev 指针：
2. 将其设置为指向被删除节点之前的节点。

这有效地“弥合”了因删除节点而产生的间隙，保持了列表的完整性。

时间复杂度分析

• 在双向链表中添加/删除 →

  $O(n)O(n)$O(n)

• 在双向链表的头部或尾部添加/删除 →

  $O(1\mathrm{})O(1)$O(1)

JavaScript 实现

经典面向对象编程

class ListNode {
  constructor(value, prev = null, next = null) {
    this.value = value;
    this.prev = prev;
    this.next = next;
  }
}

class DoublyLinkedList {
  constructor() {
    this.head = null;
    this.tail = null;
    this.size = 0;
  }

  // add a node to the head of the list
  addHead(value) {
    const newNode = new ListNode(value, null, this.head);
    if (this.head) {
      this.head.prev = newNode;
    } else {
      this.tail = newNode; // If list was empty, new node is also the tail
    }
    this.head = newNode;
    this.size++;
  }

  // Add a node to the tail of the list
  addTail(value) {
    const newNode = new ListNode(value, this.tail, null);
    if (this.tail) {
      this.tail.next = newNode;
    } else {
      this.head = newNode; // If list was empty, new node is also the head
    }
    this.tail = newNode;
    this.size++;
  }

  // Remove a node from the head of the list
  removeHead() {
    if (!this.head) return null; // List is empty
    const removedValue = this.head.value;
    this.head = this.head.next;
    if (this.head) {
      this.head.prev = null;
    } else {
      this.tail = null; // List became empty
    }
    this.size--;
    return removedValue;
  }

  // Remove a node from the tail of the list
  removeTail() {
    if (!this.tail) return null; // List is empty
    const removedValue = this.tail.value;
    this.tail = this.tail.prev;
    if (this.tail) {
      this.tail.next = null;
    } else {
      this.head = null; // List became empty
    }
    this.size--;
    return removedValue;
  }

  // Remove a node at a specific index
  removeAt(index) {
    if (index < 0 || index >= this.size) return null;
    let current;
    if (index < this.size / 2) {
      current = this.head;
      for (let i = 0; i < index; i++) {
        current = current.next;
      }
    } else {
      current = this.tail;
      for (let i = this.size - 1; i > index; i--) {
        current = current.prev;
      }
    }
    if (current.prev) current.prev.next = current.next;
    if (current.next) current.next.prev = current.prev;
    if (index === 0) this.head = current.next;
    if (index === this.size - 1) this.tail = current.prev;
    this.size--;
    return current.value;
  }

  // Get the size of the list
  getSize() {
    return this.size;
  }

  // Get the values in the list
  getValues() {
    const values = [];
    let current = this.head;
    while (current) {
      values.push(current.value);
      current = current.next;
    }
    return values;
  }
}

函数式面向对象编程

function ListNode(value, prev = null, next = null) {
  this.value = value;
  this.prev = prev;
  this.next = next;
}

function DoublyLinkedList() {
  this.head = null;
  this.tail = null;
  this.size = 0;
}

// Add a node to the head of the list
DoublyLinkedList.prototype.addHead = function(value) {
  const newNode = new ListNode(value, null, this.head);
  if (this.head) {
    this.head.prev = newNode;
  } else {
    this.tail = newNode;
  }
  this.head = newNode;
  this.size++;
};

// Add a node to the tail of the list
DoublyLinkedList.prototype.addTail = function(value) {
  const newNode = new ListNode(value, this.tail, null);
  if (this.tail) {
    this.tail.next = newNode;
  } else {
    this.head = newNode;
  }
  this.tail = newNode;
  this.size++;
};

// Remove a node from the head of the list
DoublyLinkedList.prototype.removeHead = function() {
  if (!this.head) return null;
  const removedValue = this.head.value;
  this.head = this.head.next;
  if (this.head) {
    this.head.prev = null;
  } else {
    this.tail = null;
  }
  this.size--;
  return removedValue;
};

// Remove a node from the tail of the list
DoublyLinkedList.prototype.removeTail = function() {
  if (!this.tail) return null;
  const removedValue = this.tail.value;
  this.tail = this.tail.prev;
  if (this.tail) {
    this.tail.next = null;
  } else {
    this.head = null;
  }
  this.size--;
  return removedValue;
};

// Remove a node at a specific index
DoublyLinkedList.prototype.removeAt = function(index) {
  if (index < 0 || index >= this.size) return null;
  let current;
  if (index < this.size / 2) {
    current = this.head;
    for (let i = 0; i < index; i++) {
      current = current.next;
    }
  } else {
    current = this.tail;
    for (let i = this.size - 1; i > index; i--) {
      current = current.prev;
    }
  }
  if (current.prev) current.prev.next = current.next;
  if (current.next) current.next.prev = current.prev;
  if (index === 0) this.head = current.next;
  if (index === this.size - 1) this.tail = current.prev;
  this.size--;
  return current.value;
};

// Get the size of the list
DoublyLinkedList.prototype.getSize = function() {
  return this.size;
};

// Get the values in the list
DoublyLinkedList.prototype.getValues = function() {
  const values = [];
  let current = this.head;
  while (current) {
    values.push(current.value);
    current = current.next;
  }
  return values;
};

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