MySQl資料庫必須知道的sql語句

本文給大家分享了一篇關於mysql資料庫必會sql語句加強版內容，非常不錯，具有參考借鑒價值，需要的朋友參考下吧

這一篇屬於加強版，問題和sql語句如下。

建立users表，設定id,name,gender,sal字段，其中id為主鍵 

drop table if exists users; 
create table if not exists users( 
  id int(5) primary key auto_increment, 
  name varchar(10) unique not null,   
  gender varchar(1) not null, 
  sal int(5) not null 
); 
insert into users(name,gender,sal) values('AA','男',1000); 
insert into users(name,gender,sal) values('BB','女',1200);

------- -------------------------------------------------- ----------------------------- 

一對一：AA的識別號碼是多少 

drop table if exists users; 
create table if not exists users( 
  id int(5) primary key auto_increment, 
  name varchar(10) unique not null,   
  gender varchar(1) not null, 
  sal int(5) not null 
); 
insert into users(name,gender,sal) values('AA','男',1000); 
insert into users(name,gender,sal) values('BB','女',1200); 
drop table if exists cards; 
create table if not exists cards( 
  id int(5) primary key auto_increment, 
  num int(3) not null unique, 
  loc varchar(10) not null, 
  uid int(5) not null unique, 
  constraint uid_fk foreign key(uid) references users(id) 
); 
insert into cards(num,loc,uid) values(111,'北京',1); 
insert into cards(num,loc,uid) values(222,'上海',2);

【註：inner join表示內連接】 

select u.name "姓名",c.num "身份证号" 
from users u inner join cards c 
on u.id = c.uid 
where u.name = 'AA'; 
-- 
select u.name "姓名",c.num "身份证号" 
from users u inner join cards c 
on u.id = c.uid 
where name = 'AA';

##----- ------------------------------------------ 

一對多：查詢"開發部"有哪些員工 

建立groups表 

#

drop table if exists groups; 
create table if not exists groups( 
  id int(5) primary key auto_increment, 
  name varchar(10) not null 
); 
insert into groups(name) values('开发部'); 
insert into groups(name) values('销售部');

建立emps表 

#

drop table if exists emps; 
create table if not exists emps( 
  id int(5) primary key auto_increment, 
  name varchar(10) not null, 
  gid int(5) not null, 
  constraint gid_fk foreign key(gid) references groups(id) 
); 
insert into emps(name,gid) values('哈哈',1); 
insert into emps(name,gid) values('呵呵',1); 
insert into emps(name,gid) values('嘻嘻',2); 
insert into emps(name,gid) values('笨笨',2);

查詢"開發部"有哪些員工 

#

select g.name "部门",e.name "员工" 
from groups g inner join emps e 
on g.id = e.gid 
where g.name = '开发部'; 
-- 
select g.name "部门",e.name "员工" 
from groups g inner join emps e 
on g.id = e.gid 
where g.name = '开发部';

##--------- ---------------------------------------------- 

#多對多：查詢"趙"教過哪些學生 

建立students表 

drop table if exists students; 
create table if not exists students( 
  id int(5) primary key auto_increment, 
  name varchar(10) not null 
); 
insert into students(name) values('哈哈'); 
insert into students(name) values('嘻嘻');

##建立teachers表 

#

drop table if exists teachers; 
create table if not exists teachers( 
  id int(5) primary key auto_increment, 
  name varchar(10) not null 
); 
insert into teachers(name) values('赵'); 
insert into teachers(name) values('刘');

建立middles表   primary key(sid,tid)  表示組合主鍵，這兩個欄位的整體要唯一 

#

drop table if exists middles; 
create table if not exists middles( 
  sid int(5), 
  constraint sid_fk foreign key(sid) references students(id), 
  tid int(5), 
  constraint tid_fk foreign key(tid) references teachers(id), 
  primary key(sid,tid)  
); 
insert into middles(sid,tid) values(1,1); 
insert into middles(sid,tid) values(1,2); 
insert into middles(sid,tid) values(2,1); 
insert into middles(sid,tid) values(2,2);

查詢"趙"教過哪些學生 

#

select t.name "老师",s.name "学生" 
from students s inner join middles m inner join teachers t 
on (s.id=m.sid) and (m.tid=t.id) 
where t.name = '赵'; 
-- 
select t.name "老师",s.name "学生" 
from students s inner join middles m inner join teachers t  
on (s.id=m.sid) and (t.id=m.tid) 
where t.name = "赵";

------- -------------------------------------------------- ----------------------------------------------- 

#將5000元（含）以上的員工標識為"高薪"，否則標識為"起薪" 

將薪水為NULL的員工標識為"無薪" 

#將5000元（含）以上的員工標識為"高薪"，否則標識為"起薪" 

將7000元的員工標識為"高薪",6000元的員工識別為"中薪",5000元則標識為"起薪",否則標識為"試用薪"

------------------- -------------------------------------------------- ------------------------------------ 

內連線（等值連線）：查詢顧客姓名，訂單編號，訂單價格 

【註：customers c inner join orders o使用了別名，以後o就代表orders】 

select c.name "客户姓名",o.isbn "订单编号",o.price "订单价格" 
from customers c inner join orders o 
on c.id = o.customers_id; 
-- 
select c.name "客户姓名",o.isbn "订单编号",o.price "订单价格" 
from customers c inner join orsers o 
on c.id = o.customers_id;

on+兩個表連接的條件.一張表的主鍵，一張表的外鍵 

#內連接：只能查詢出二張表中根據連接條件都存在的記錄，有點類似數學中交集 

--------------------------------------- ------------- 

外部連線：依客戶分組，查詢每位客戶的姓名和訂單數 

外連線：既可依連線條件查詢出二張表中都存在的記錄，也能根據一方，強行將另一方就算不滿兄條件的記錄也能查詢出來 

外連接可以細分為：

<左外连接 : 以左侧为参照，left outer join表示 
select c.name,count(o.isbn) 
from customers c left outer join orders o 
on c.id = o.customers_id 
group by c.name; 
-- 
>右外连接 : 以右侧为参照，right outer join表示 
select c.name,count(o.isbn) 
from orders o right outer join customers c 
on c.id = o.customers_id 
group by c.name;

left outer join表示左邊的內容都會顯現出來，例如customers c left out join 表示會把customers中的某列所有內容都找出來  

# #------------------------------------------------- ----- 

自連接：求出AA的老闆是EE。把自己想像成兩張表。左右各一張 

select users.ename,bosss.ename 
from emps users inner join emps bosss 
on users.mgr = bosss.empno; 
select users.ename,bosss.ename 
from emps users left outer join emps bosss 
on users.mgr = bosss.empno;

------------------------ -------------------------------------------------- --------------------- 

示範MySQL中的函數（查詢手冊）  

#日期時間函數： 

#

select addtime('2016-8-7 23:23:23','1:1:1');  时间相加 
select current_date(); 
select current_time(); 
select now(); 
select year( now() ); 
select month( now() ); 
select day( now() ); 
select datediff('2016-12-31',now());

字串函數：

#

select charset('哈哈'); 
select concat('你好','哈哈','吗'); 
select instr('www.baidu.com','baidu'); 
select substring('www.baidu.com',5,3);

數學函數： 

select bin(10); 
select floor(3.14);//比3.14小的最大整数---正3 
select floor(-3.14);//比-3.14小的最大整数---负4 
select ceiling(3.14);//比3.14大的最小整数---正4 
select ceiling(-3.14);//比-3.14大的最小整数---负3，一定是整数值 
select format(3.1415926,3);保留小数点后3位，四舍五入 
select mod(10,3);//取余数 
select rand();//

加密函數： 

select md5('123456'); 

#回傳32位元16進制數e10adc3949ba59abbe56e057f20f883e  

示範MySQL中流程控制語句 

use json; 
drop table if exists users; 
create table if not exists users( 
  id int(5) primary key auto_increment, 
  name varchar(10) not null unique, 
  sal int(5) 
); 
insert into users(name,sal) values('哈哈',3000); 
insert into users(name,sal) values('呵呵',4000); 
insert into users(name,sal) values('嘻嘻',5000); 
insert into users(name,sal) values('笨笨',6000); 
insert into users(name,sal) values('明明',7000); 
insert into users(name,sal) values('丝丝',8000); 
insert into users(name,sal) values('君君',9000); 
insert into users(name,sal) values('赵赵',10000); 
insert into users(name,sal) values('无名',NULL);

#（含5000

#為"高薪"，否則標識為"起薪"

select name "姓名",sal "薪水", 
    if(sal>=5000,"高薪","起薪") "描述" 
from users;

#將薪水為NULL的員工標識為"無薪"

select name "姓名",ifnull(sal,"无薪") "薪水" 
from users;

#將5000元（含）以上的員工標識為"高薪"，否則標識為"起薪"

select name "姓名",sal "薪水", 
    case when sal>=5000 then "高薪" 
    else "起薪" end "描述" 
from users;

###將7000元的員工識別為"高薪"，6000元的員工標識為"中薪",5000元則標識為"起薪"，否則標識為"試用薪"#########

select name "姓名",sal "薪水", 
    case sal 
      when 3000 then "低薪" 
      when 4000 then "起薪" 
      when 5000 then "试用薪" 
      when 6000 then "中薪" 
      when 7000 then "较好薪" 
      when 8000 then "不错薪" 
      when 9000 then "高薪" 
      else "重薪" 
    end "描述" 
from users;

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