使用可變參數模板漂亮地打印std::tuple
之前關於漂亮打印STL 容器的討論的後續內容,我們的目標是使用可變參數擴展此功能以包括std::tuple
問題
對於std::pair,我們之前實現了一個用於漂亮打印的自訂運算子重載:
std::ostream & operator<<(std::ostream &o, const std::pair<S,T> &p) { return o << "(" << p.first << ", " << p.second << ")"; }
目標是為std::tuple 建立類似的構造。
解決方案
namespace aux { // Index sequence utility template<std::size_t...> struct seq {}; template<std::size_t N, std::size_t... Is> struct gen_seq : gen_seq<N-1, N-1, Is...> {}; template<> struct gen_seq<0> : seq<> {}; // Recursive printing function using indices template<class Ch, class Tr, class Tuple, std::size_t... Is> void print_tuple(std::basic_ostream<Ch,Tr>& os, Tuple const& t, seq<Is...>) { using swallow = int[]; (void)swallow{0, (void(os << (Is == 0? "" : ", ") << std::get<Is>(t)), 0)...}; } } // aux:: template<class Ch, class Tr, class... Args> auto operator<<(std::basic_ostream<Ch, Tr>& os, std::tuple<Args...> const& t) -> std::basic_ostream<Ch, Tr>& { os << "("; aux::print_tuple(os, t, aux::gen_seq<sizeof...(Args)>()); return os << ")"; }
額外的通用性
要增強通用性,請為分隔符號處理添加部分專業化:
// Delimiters for tuple template<class... Args> struct delimiters<std::tuple<Args...>, char> { static const delimiters_values<char> values; }; template<class... Args> const delimiters_values<char> delimiters<std::tuple<Args...>, char>::values = { "(", ", ", ")" }; template<class... Args> struct delimiters<std::tuple<Args...>, wchar_t> { static const delimiters_values<wchar_t> values; }; template<class... Args> const delimiters_values<wchar_t> delimiters<std::tuple<Args...>, wchar_t>::values = { L"(", L", ", L")" };
整合這些變更進入運算符
template<class Ch, class Tr, class... Args> auto operator<<(std::basic_ostream<Ch, Tr>& os, std::tuple<Args...> const& t) -> std::basic_ostream<Ch, Tr>& { typedef std::tuple<Args...> tuple_t; if(delimiters<tuple_t, Ch>::values.prefix != 0) os << delimiters<tuple_t,char>::values.prefix; aux::print_tuple(os, t, aux::gen_seq<sizeof...(Args)>()); if(delimiters<tuple_t, Ch>::values.postfix != 0) os << delimiters<tuple_t,char>::values.postfix; return os; } template<class Ch, class Tr, class Tuple, std::size_t... Is> void print_tuple(std::basic_ostream<Ch, Tr>& os, Tuple const& t, seq<Is...>) { using swallow = int[]; char const* delim = delimiters<Tuple, Ch>::values.delimiter; if(!delim) delim = ""; (void)swallow{0, (void(os << (Is == 0? "" : delim) << std::get<Is>(t)), 0)...}; }
以上是如何使用可變參數模板漂亮地列印“std::tuple”?的詳細內容。更多資訊請關注PHP中文網其他相關文章!