PHP는 날짜 사이의 일수 차이(특정 시간과 현재 시간 사이의 시차)를 계산합니다.

function count_days($a,$b){
 $a_dt=getdate($a);
 $b_dt=getdate($b);
 $a_new=mktime(12,0,0,$a_dt['mon'],$a_dt['mday'],$a_dt['year']);
 $b_new=mktime(12,0,0,$b_dt['mon'],$b_dt['mday'],$b_dt['year']);
 return round(abs($a_new-$b_new)/86400);
}
//今天与2008年10月11日相差多少天
$date1=strtotime(time());
$date1=strtotime('10/11/2008');
$result=count_days($date1,$date2);
echo $result;
?>

方法2：

//今天与2008年9月9日相差多少天
$Date_1=date("Y-m-d");
$Date_2="2008-10-11";
$d1=strtotime($Date_1);
$d2=strtotime($Date_2);
$Days=round(($d2-$d1)/3600/24);
echo "今天与2008年10月11日相差".$Days."天";
?>

PHP获得任意时间与当前时间的时间差

代码：

#功能：获得任意时间与当前时间的时间差
function QueryDays($datestr){
#格式化时间
$da=preg_split("/(-| |:)/i",$datestr);
$nowyear=date("Y");
$nowmon=date("n");
$nowday=date("d");
$nowtimes=mktime(0,0,0,$nowmon,$nowday,$nowyear);
$pdtimes= mktime(0,0,0,$nowmon,$nowday,$nowyear-1);
$bjtimes= mktime(0,0,0,$da[1],$da[2],$da[0]);
#判断所给出的时间是不是在一年内
if ($bjtimes>=$pdtimes and $bjtimesreturn (floor(strftime("%j",mktime(0,0,0,$nowmon,$nowday,$nowyear)-mktime($da[3],$da[4],$da[5],$da[1],$da[2],$da[0]))));
}else{
$loop=$nowyear-$da[0];
$totaldays=(floor(strftime("%j",mktime(0,0,0,$nowmon,$nowday,$nowyear)-mktime(0,0,0,1,1,$nowyear))));
for($i=1;$ifor($j=12;$j>=1;$j--){
if ($da[0]==$nowyear-$i and $da[1]==$j){
$days=MonDays($nowyear-$i,$j);
return $totaldays =$days-$da[2];
break;
}else{
$days=MonDays($nowyear-$i,$j);
$totaldays =$days;
}//end else
 }//end for
}//end for
}//end else
}//end function
#取得月分的天数
function MonDays($year,$month){
switch ($month){
case "1":
case "3":
case "5":
case "7":
case "8":
case "10":
case "12": $days=31;break;
case "4":
case "6":
case "9":
case "11": $days=30;break;
case "2":
if (checkdate($month,29,$year)){
$days=29;
}else{
$days=28;
}//end else
break;
}//end switch
return $days;
}//end function
$datestr="2002-1-14 9:47:20";
echo QueryDays($datestr);
?>

PHP计算两个时间相差的年月时分秒

PHP如何计算两个时间相差几年几月几时几分几秒

先将两个时间转化为时间戳，然后相减得到两个时间相差的秒数，最后进行一些算术就可以得到两个时间相差的年月日时分秒了。

代码：

$time1 = "2008-6-15 11:49:59"; //第一个时间
$time2 = "2007-5-5 12:53:28"; //第二个时间
$t1 = strtotime($time1);
$t2 = strtotime($time2);
$t12 = abs($t1-$t2);
$start = 0;
$string = "两个时间相差：";
$y = floor($t12/(3600*24*360));
if($start || $y )
{
$start = 1;
$t12 -= $y*3600*24*360;
$string .= $y."年";
}
$m = floor($t12/(3600*24*31));
if($start || $m)
{
$start = 1;
$t12 -= $m*3600*24*31;
$string .= $m."月";
}
$d = floor($t12/(3600*24));
if($start || $d)
{
$start = 1;
$t12 -= $d*3600*24;
$string .= $d."天";
}
$h = floor($t12/(3600));
if($start || $h)
{
$start = 1;
$t12 -= $h*3600;
$string .= $h."时";
}
$s = floor($t12/(60));
if($start || $s)
{
$start = 1;
$t12 -= $s*60;
$string .= $s."分";
}
$string .= "{$t12}秒";
echo $string;
?>