집 >데이터 베이스 >MySQL 튜토리얼 >sqllite 判断 某个id是否存在于表中了,如果存在则不插入,不存
判断某个id是否存在于表中了,如果存在则不插入,不存在则插入 无 INSERT INTO USER (email,ADDTIME) (SELECT 'email','addTime' FROM USER u2 JOIN( SELECT COUNT(*) num FROM USER u1 WHERE u1.id = 87) u3 ON u3.num 1 LIMIT 1)
判断 某个id是否存在于表中了,如果存在则不插入,不存在则插入INSERT INTO USER (email,ADDTIME) (SELECT 'email','addTime' FROM USER u2 JOIN( SELECT COUNT(*) num FROM USER u1 WHERE u1.id = 87) u3 ON u3.num < 1 LIMIT 1)