この記事では主に、特定の参考値を持つ SQL の使用方法を紹介します。必要な友達はそれを参照してください
drop table if exists tbl_a;create table tbl_a(
key1 varchar(10),
col_1 int4,
col_2 int4,
col_3 int4
);insert into tbl_a values('A', 2, 3, 4);
insert into tbl_a values('B', 0, 7, 9);
insert into tbl_a values('c', 5, 1, 6);
drop table if exists tbl_b;create table tbl_b(
key1 varchar(10),
col_1 int4,
col_2 int4,
col_3 int4
);
insert into tbl_b values('A', 2, 3, 4);
insert into tbl_b values('B', 0, 7, 9);
insert into tbl_b values('c', 5, 1, 6);-- ## 如果union a b 行数一致则两张表相等 select count(1) row_cnt from ( select *
from tbl_A union
select * from tbl_b
) tmp
;
2. 差分セットを使用してリレーショナル除算演算を実装します
(select * from tbl_a except
select * from tbl_b) union all
(select * from tbl_b except
select * from tbl_a);
drop table if exists skills;create table skills(
skill varchar(10)
);insert into skills values('oracle');
insert into skills values('unix');insert into skills values('java');drop table if exists empskills;create table empskills(
emp varchar(10),
skill varchar(10)
);insert into empskills values('相田','oracle');
insert into empskills values('相田','unix');
insert into empskills values('相田','java');
insert into empskills values('相田','c#');
insert into empskills values('神奇','oracle');
insert into empskills values('神奇','unix');
insert into empskills values('神奇','java');
insert into empskills values('平井','oracle');
insert into empskills values('平井','unix');
insert into empskills values('平井','PHP');
insert into empskills values('平井','Perl');
insert into empskills values('平井','C++');
insert into empskills values('若田部','Perl');
insert into empskills values('度来','oracle');
3. 等しいサブセットを見つけます
--把除法变成减法select distinct emp from empskills es1 where not exists (select skill from skills expect select skill from empskills es2 where es1.emp = es2.emp);
drop table if exists supparts;create table supparts( sup varchar(10), part varchar(10) );insert into supparts values('A', '螺丝'); insert into supparts values('A', '螺母'); insert into supparts values('A', '管子'); insert into supparts values('B', '螺丝'); insert into supparts values('B', '管子'); insert into supparts values('C', '螺丝'); insert into supparts values('C', '螺母'); insert into supparts values('C', '管子'); insert into supparts values('D', '螺丝'); insert into supparts values('D', '管子'); insert into supparts values('E','保险丝'); insert into supparts values('E', '螺母'); insert into supparts values('E', '管子'); insert into supparts values('F','保险丝');
4. 重複する行を削除します
select a.sup s1, b.sup s2 from supparts a, supparts b where a.sup < b.sup -- 生成供应商的全部组合 and a.part = b.part -- 条件1:经营同种类型的零件 group by a.sup, b.suphaving count(*) = (select count(1) -- 条件2:经营的零件的数量种类相同 a = 中间数 from supparts c where c.sup = a.sup) and count(*) = (select count(1) -- 条件2:经营的零件的数量种类相同 b = 中间数 from supparts d where d.sup = b.sup) ;
drop table if exists products;create table products( rowid int4, name1 varchar(10), price int4 );insert into products values(1,'苹果',50);insert into products values(2,'橘子',100); insert into products values(3,'橘子',100);insert into products values(4,'橘子',100); insert into products values(5,'香蕉',80);-- 删除重行高效SQL语句(1):通过EXCEPT求补集delete from productswhere rowid in (select rowid -- 全部rowid from products except -- 减去 select max(rowid) -- 要留下的rowid from products group by name1, price );-- 删除重行高效SQL语句(2):通过not indelete from products where rowid not in (select max(rowid) from products group by name1, price );コンテンツの大部分「SQL Advanced Textbook」から出てきたのでメモしておきます。演習内のコードの一部はオリジナルです。
以上がSQLを使用した設定操作の詳細内容です。詳細については、PHP 中国語 Web サイトの他の関連記事を参照してください。