本帖最后由 hxlb520 于 2014-09-19 08:53:23 编辑 我想在foreach()循环中只显示没有下级的大栏目(例如只显示代码中的大栏目一,大栏目四),有下级栏目的不显示 ,如何判断呢?
cid=栏目ID,name=栏目名称,parent_cid=子栏目的上级栏目ID
{"seller_cat":[
{"cid":"1","name":"大栏目一","parent_cid":"0"},
{"cid":"2","name":"大栏目二","parent_cid":"0"},
{"cid":"3","name":"子栏目二","parent_cid":"2"},
{"cid":"4","name":"子栏目三","parent_cid":"2"},
{"cid":"5","name":"大栏目三","parent_cid":"0"},
{"cid":"6","name":"子栏目一","parent_cid":"5"},
{"cid":"7","name":"大栏目四","parent_cid":"0"}
]}}
------解决思路----------------------类方法,可以参考下。
$a = json_decode($s);<br>$ar = array();<br>foreach($a->seller_cat as $t) {<br> if($t->parent_cid == 0 && ! array_filter($a->seller_cat, array(new T($t->cid), 'filter')))<br> $ar[] = $t->name;<br>}<br>print_r($ar);<br>class T {<br> private $cid;<br><br> function __construct($cid) {<br> $this->cid = $cid;<br> }<br><br> function filter($v) {<br> return $v->parent_cid == $this->cid;<br> }<br>}
------解决思路----------------------foreach($a->seller_cats->seller_cat as $t) {
if($t->parent_cid == 0 && ! array_filter($a->seller_cats->seller_cat, array(new T($t->cid), 'filter')))
$ar[] = $t->name;
}