mysql
1、select role_auth_ids from test_role where role_name='经理' 的执行结果:
+------------+
role_auth_ids
+------------+
1,2,3
2、select auth_name from test_auth where auth_id in (1,2,3)的执行结果:
+------+
auth_name
+------+
商品管理
商品添加
商品编辑
但是,将1、2条语句合并后,即select auth_name from test_auth where auth_id in (select role_auth_ids from test_role where role_name='经理'),执行结果只有一条数据,也就是只有商品管理一个数据。这是why?
SELECT auth_name FROM test_auth WHERE auth_id IN (SELECT replace(concat('''',role_auth_ids,''''),',',''',''') FROM test_role WHERE role_name = '经理 ') 给in子句加上单引号也不行..................
请教各位大神我该如何才能从通过test_role中role_auth_ids查询出对应的test_auth表中的auth_name呢?

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