PHP的header跳转之前不能有任何内容输出，因为PHP开始执行的时候就已经向浏览器送出HTTP头信息，之后就不再允许更改了；且“header("location:xx")”进行跳转时，location和“:”号间不能有空格，否则会出错。
问题：
今天header(\"Location: $url\"),以往跳转总是可以的,今天却不动,只是输出结果,以往自己要确认检查，$url的值获取的是否正确,所以在前面加了echo $url；来调试用,结果就导致了header函数的无效.
解决方法：
在PHP中用header("location:test.php")进行跳转要注意以下几点:
1、location和“:”号间不能有空格，否则会出错.//phpfensi.com
2、在用header前不能有任何的输出，包括include的页面中标签“?>”后不能有空格.
3、header后的PHP代码还会被执行。
PHP的 header 跳转之前不能有任何内容输出,因为PHP开始执行的时候就已经向浏览器送出HTTP头信息,之后就不再允许更改了.
但是如果必须要在输出之后再处理header信息的话可以使用 ob_start() ob_end_flush() 来缓存一下要发送的内容,等到header继续再发送内容.
或者一个更简单的办法，修改php.ini，找到 output_buffering=Off 修改为 output_buffering=4096。
更多相关知识，请访问 PHP中文网！！
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