Compatibility rules for Java function generics

The compatibility rules of Java function generics ensure type safety. Rules include: same type parameter lists, same type parameter bounds, and contravariant and covariant type parameters. For example, > is compatible with > (contravariant), while is compatible with

Compatibility rules for Java function generics

Java generic functions allow us to write code in a type-safe manner, But not following the correct compatibility rules can lead to compile-time errors. Let’s sort out the rules to avoid such problems.

Rule 1: The type parameter lists are the same

Only function types with the same parameter list are compatible. So the following example will result in an error:

public <T> void func1(T v) {}
public <U> void func2(U v) {}

Rule 2: Type parameters have the same bounds

Bounds define the allowed values ​​of a generic type. Functions are incompatible if they have different bounds for parameters of the same type. For example:

public <T extends Comparable<T>> void func1(T v) {}
public <T extends Number> void func2(T v) {}

Rule 3: Contravariant and covariant type parameters

• Contravariance: If subclass type T can replace superclass type S, then <t></t> is type compatible with <s></s>. For example, <list>></list> is compatible with <list>></list>.
• Covariance: If the superclass type T can replace the subclass type S, then the <s></s> type is compatible with <t></t>. For example, <string></string> is compatible with <object></object>.

Practical case

Consider the following code:

public <T extends Animal> void func1(T t) {
    // 代码...
}

public void func2(Cat c) {
    // 代码...
}

func1 Expects an Animal or an instance of its subclass. func2 Expects a Cat instance. Since Cat extends Animal, func1 is compatible with func2 and can receive Cat type parameters.

Conclusion

It is crucial to follow the compatibility rules for function generics to avoid compile-time errors and ensure type safety.

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