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Why does a Linux process need to sleep?
Linux is a multi-tasking operating system that supports multiple processes running at the same time. In Linux, a process has three states: running state, ready state and blocked state. Among them, the blocking state is also called the dormant state, which refers to the state where the process temporarily stops running because it is waiting for an event to occur. In order to efficiently utilize computing resources, Linux processes need to enter a dormant state under some circumstances.
#include <stdio.h> #include <unistd.h> #include <fcntl.h> int main() { int fd = open("file.txt", O_RDONLY); if (fd == -1) { perror("Error opening file"); return 1; } char buffer[100]; ssize_t bytes_read = read(fd, buffer, sizeof(buffer)); if (bytes_read == -1) { perror("Error reading file"); return 1; } // Perform some other operations close(fd); return 0; }
In the above example, the process reads the file through the read
function. When read
is called, the process will sleep until the file operation is completed.
#include <stdio.h> #include <signal.h> void handler(int sig) { printf("Received signal %d ", sig); } int main() { signal(SIGUSR1, handler); printf("Waiting for signal... "); pause(); // The process enters sleep state and waits for the signal to trigger printf("Signal received. Continuing... "); return 0; }
In the above example, the process enters sleep state through the pause
function, waiting to receive the user-defined signal SIGUSR1
.
To sum up, Linux processes need to sleep in order to better manage system resources, avoid resource waste and improve system efficiency. By rationally using the hibernation mechanism, the Linux system can make full use of computing resources and improve the overall system performance.
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