php editor Xiaoxin will introduce to you how to solve the deadlock problem. Deadlock is a common problem in concurrent programming. Deadlock occurs when two or more processes wait for each other to release resources. In order to solve this problem, we can use some common methods, such as using mutex locks, avoiding resource competition, using timeout mechanisms, etc. Through reasonable design and adjustment, we can effectively avoid the occurrence of deadlock and improve the concurrency and stability of the program. Next, let’s take a closer look at how to solve the deadlock problem!
Question content
I have two goroutines, which are two testxxx functions during testing. I use condition variables to synchronize these goroutines. However, once one of the tests fails, the other one is waiting for a signal. The deadlock is coming. Also, if testfunctionb fails, I want testfunctiona to fail too.
var cond sync.cond func testfunctiona(t *testing.t){ // ... some codes... cond.wait() } func testfunctionb(t *testing.t){ // ... some codes... t.fail() // ... some codes... cond.broadcast() }
I have tried some methods, such as:
var cond sync.Cond var A_t *testing.T func TestFunctionA(t *testing.T){ // ... Some codes... A_t = t // ... Some codes... cond.Wait() } func TestFunctionB(t *testing.T){ // ... Some codes... t.Cleanup(func(){ if !A_t.Failed(){ A_t.Fail() } cond.Broadcast() }) t.Fail() // ... Some codes... cond.Broadcast() }
But when functionb has no errors, a_t.fail() will still be triggered.
I am also considering using context.context(). However, I don't know how to run the test function within the context. Thank you for reading my question! I appreciate any comments or discussion!
Workaround
One test should not interact with another test. However, when using subtests we can share anything between test cases.
Here is an example:
package main import ( "errors" "testing" ) func TestFruits(t *testing.T) { var err error t.Run("test apple", getTestAppleFunc(&err)) t.Run("test banana", getTestBananaFunc(&err)) } func handleError(t *testing.T, err *error) { if err != nil && *err != nil { t.Error(*err) } } func getTestAppleFunc(err *error) func(*testing.T) { return func(t *testing.T) { handleError(t, err) *err = errors.New("Apple failed") } } func getTestBananaFunc(err *error) func(*testing.T) { return func(t *testing.T) { handleError(t, err) } }
- In the functions
gettestbananafunc
andgettestapplefunc
, the error pointer is passed as a parameter. - In the above example, the first execution is
gettestapplefunc
. - If there is an incorrect assignment in
gettestapplefunc
(as in the example above), thegettestbananafunc
function will fail.
The above is the detailed content of How to resolve deadlock (waiting for signal of failed test). For more information, please follow other related articles on the PHP Chinese website!

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