Given an array consisting of 0, 1 and 2, sort the elements in order such that all 0's come before 1's and all 2's come last. We have to sort all elements of the array in-place.
We can use the DNF (Dutch Flag) sorting algorithm to solve this problem. For example,
Input-1 -
arr[ ]= {2,0,0,1,2,1 }
Output -
0 0 1 1 2 2
Explanation − Use DNF The sorting algorithm sorts the given array containing 0, 1 and 2, it will output as {0,0,1,1,2,2}.
Input-2 −
arr[ ] = {0,1,1,2,1,1,0}
Output -
0 0 1 1 1 1 2
Explanation − Use DNF sorting algorithm Sort the given array of elements containing 0, 1 and 2, it will output as {0,0,1,1,1,1,2}.
Method to solve this problem
In the given array of 0, 1 and 2, we can use the DNF sorting algorithm.
DNF sorting algorithm − This algorithm requires 3 pointers to traverse the entire array and exchange the necessary elements.
Create a low pointer at the beginning of the array and a high pointer pointing to the end of the array.
Find the midpoint of the array and create a midpointer that iterates from the beginning to the end of the array.
If the middle pointer of the array is '0', swap the element pointing to the low pointer. Added low and mid pointers.
If the middle pointer of the array is '2', swap it with the element pointing to the high pointer. Increase the middle pointer and decrease the high pointer.
If the middle pointer of the array is '1', increase the middle pointer.
Example
Demonstration
public class Solution { public static void binarySorting(int arr[], int n){ int low=0; int high= n-1; int mid=0; while(mid<=high){ if(arr[mid]==0){ int temp= arr[mid]; arr[mid]= arr[low]; arr[low]= temp; mid++; low++; } if(arr[mid]==1){ mid++; } if(arr[mid]==2){ int temp= arr[mid]; arr[mid]= arr[high]; arr[high]= temp; high--; } } } public static void print(int arr[], int n){ for (int i = 0; i < n; i++) System.out.print(arr[i] +" "); } public static void main(String[] args){ int arr[] ={ 0,0,1,0,1,0,1,2,2}; int n = arr.length; binarySorting(arr, n); print(arr, n); } }
Output
Running the above code will generate the following output:
0 0 0 0 1 1 1 1 2
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