Translate the following into Chinese: C programming to sum the first n terms of the sequence 0.6, 0.06, 0.006, 0.0006,...

The given series 0.6,0 .o6,.... is a geometric series where each element is the previous element divided by 10. Therefore, to find the sum of the series, we must apply the GP one formula for r whose sum is less than 1 (in our case r=0.1).

Sum = 6/10 [1- (1/10)n/(1-1/10)]
Sum = 6/9 [1- (1/10)n]
Sum = 2/3[1- (1/10n)]

Example

#include <stdio.h>
#include <math.h>
int main() {
   int n = 6;
   float sum = 2*((1 - 1 / pow(10, n)))/3;
   printf("sum = %f", sum);
}

Output

sum = 0.666666

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