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Suppose we have one array. we have to count how many of the elements present in the array prime number of times. So if the array is {1, 2, 2, 0, 1, 5, 2, 5, 0, 0, 1, 1}, then 1 is present 4 times, 2 is present 3 times, 0 is present 3 times, and 5 is present 2 times. So there are three elements {2, 0, 5} that have occurred prime number of times. So the count will be 3.
Begin count := 0 define map with int type key and int type value for each element e in arr, do increase map.key(arr).value done for each key check whether the value corresponding the value is prime or not, if prime, then increase count. return count End
#include <iostream> #include <map> using namespace std; bool isPrime(int n){ for(int i = 2; i<=n/2; i++){ if(n % i == 0){ return false; } } return true; } int countPrimeOcurrence(int arr[], int n){ int count = 0; map<int, int> freq_map; for(int i = 0; i<n; i++){ freq_map[arr[i]]++; //increase the frequency } for (auto it = freq_map.begin(); it != freq_map.end(); it++) { if (isPrime(it->second)) count++; } return count; } int main() { int arr[] = {1, 2, 2, 0, 1, 5, 2, 5, 0, 0, 1, 1}; int n = sizeof(arr)/sizeof(arr[0]); cout << "Prime frequency count: " << countPrimeOcurrence(arr, n); }
Prime frequency count: 3
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