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If given a number (two, three or four digits), reverse the position of each number from front to back, and then vice versa, and then whether the output number after reversing all elements is the same then it It's a palindrome number.
String - String is a storage capsule or a storage method by which we can store a sequence of characters in a Java program.
Array - An array is a collection of similar types of data placed in different locations in a sequential form, making it easier to calculate where the data is in a program by simply adding it to a survey basic data.
Let us understand this through an example -
Given Input: a = 102022220201 Output : Reverse of a = 102022220201 //The Number Is Palindrome = YES//
Given Input: b =20011997 Output : Reverse of b = 79911002 //The Number Is Palimdrome = NO//
This is a general algorithm for reversing a number and finding if it is a palindrome -
Step 1 - Check the number of palindromes.
Step 2 - The number should be saved in a non-persistent variable.
Step 3 - Change the numbers.
Step 4 - Now check the number in the temporary variable with the reversed number.
Step 5- If both numbers remain the same or identical, then "it is a palindrome number".
Step 6 - Either/or "This is not".
{ int a,res=0,m; Scanner sc=new Scanner(System.in); System.out.println("Enter a number which you want to be reversed"); } m=sc.nextInt(); for( ;m!=0; ) { a=m%10; res=(res*10)+a; m=m/10; }
if (originalNum1 == reversedNum1) { System.out.println(originalNum1 + " is a Palindrome number."); } else { System.out.println(originalNum1 + " is not a Palindrome number."); }
Let us look at the palindrome program in Java. This would be the simplest form of a palindrome program.
The following methods are very useful for checking palindrome numbers -
Check if a number is a palindrome by using strings and arrays.
Find out palindrome number by using string in Java.
By checking whether the array is a palindrome.
Steps to check if a number is a palindrome -
Initialization of flag not set or flag value is 0.
Set the array size to n/2.
Check the conditions of the loop. Then set the flag value to 1.
Interruption.
The loop ends and the result is obtained.
import java.util.*; public class palindromeTest{ public static void main(String args[]){ int n; System.out.println("Enter a number to test"); Scanner sc = new Scanner (System.in); n=sc.nextInt(); int r=0 ,q=0 ,num=0 ,p=0; num= n; while(n!=0){ r = r%10; q = n/10; p = p*10+r ; n = q; } if (num==p){ System.out.println("the number is a palindrome number"); } else{ System.out.print("the number is not palindrome"); } } }
Enter a number to test 1111 the number is not palindrome
A palindrome number if get reversed, it will return the same number as the input provided. Using the StringBuffer method with the one way reverse(), we can check the palindrome number by using Java. In below exmaple we will check whether the input string is palindrome or not.
public class Main { public static void main(String[] args) { String str = "Radar2022", reverseStr2 = ""; int strLength1 = str.length(); for (int i = (strLength1 - 1); i >=0; --i) { reverseStr2 = reverseStr2 + str.charAt(i); } if (str.toLowerCase().equals(reverseStr2.toLowerCase())) { System.out.println(str + " -is a Palindrome String."); } else { System.out.println(str + " -is not a Palindrome String."); } } }
Radar2022 -is not a Palindrome String.
There are two procedures to check whether the array is a palindrome.
Returns true if there is only one character in the string.
Otherwise, just compare the first and last characters and put them in a recursive method.
public class findapalindrome { static void palindrome(int arr[], int n){ int flag7 = 0; for (int i = 0; i <= n / 2 && n != 0; i++) { if (arr[i] != arr[n - i - 1]) { flag7 = 1; break; } } if (flag7 == 1) System.out.println("The String Is Not Palindrome"); else System.out.println("The String Is Palindrome"); } public static void main(String[] args){ int arr[] = { 100, 200, 300, 222, 1111 }; int n = arr.length; palindrome(arr, n); } }
The String Is Not Palindrome
After definitions and some theory-based procedures, it can be easily said that a palindrome is a number that remains unchanged even after changing the original number.
All these explanations are properly described with examples and for better understanding we have also provided sample programs based on three different methods.
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