Go language regular expression tips: how to match consecutive repeated characters

Go Language Regular Expression Tips: How to Match Continuously Repeating Characters

Regular expression is a powerful tool for matching and manipulating strings. In the Go language, there is built-in support for regular expressions, through which you can easily match, find, and replace strings. This article will introduce how to use regular expressions to match consecutive repeated characters in the Go language.

In regular expressions, use the repetition qualifier to match a specified number of repeated characters. Common repeating qualifiers are: *, , ?, {n}, {n,} and {n,m}.

* is used to match zero or more repeating characters. For example, the regular expression ab*c can match ac, abc , abbc and other strings.

is used to match one or more repeated characters. For example, the regular expression ab c can match abc, abbc , abbbc and other strings.

? is used to match zero or one repeated characters. For example, the regular expression ab?c can match ac, abc and other strings.

{n} is used to match exactly n repeated characters. For example, the regular expression ab{2}c can match abbc.

{n,} is used to match at least n repeated characters. For example, the regular expression ab{2,}c can match abbc, abbbc, abbbbc and other strings.

{n,m} is used to match at least n and no more than m repeated characters. For example, the regular expression ab{2,4}c can match # Strings such as ##abbc, abbbc, abbbbc.

The following is a sample program that demonstrates how to use regular expressions to match consecutively repeated characters:

package main

import (
    "fmt"
    "regexp"
)

func main() {
    str := "aaa bbb cccc dddd"

    // 使用正则表达式匹配两个以上连续的a字符
    reg := regexp.MustCompile(`a{2,}`)
    result := reg.FindAllString(str, -1)
    fmt.Printf("连续的a字符: %v
", result)

    // 使用正则表达式匹配三个以上连续的b字符
    reg = regexp.MustCompile(`b{3,}`)
    result = reg.FindAllString(str, -1)
    fmt.Printf("连续的b字符: %v
", result)

    // 使用正则表达式匹配四个以上连续的c字符
    reg = regexp.MustCompile(`c{4,}`)
    result = reg.FindAllString(str, -1)
    fmt.Printf("连续的c字符: %v
", result)

    // 使用正则表达式匹配连续的d字符，不限数量
    reg = regexp.MustCompile(`d+`)
    result = reg.FindAllString(str, -1)
    fmt.Printf("连续的d字符: %v
", result)
}

Run the above sample program and output the following results:

连续的a字符: [aaa]
连续的b字符: []
连续的c字符: [cccc]
连续的d字符: [dddd]

In the example In the program, we first define a string

str, which contains multiple consecutive repeating characters. Then, we use the regular expression a{2,} to match more than two consecutive a characters, and the regular expression b{3,} to match more than three consecutive a characters b character, use the regular expression c{4,} to match more than four consecutive c characters, use the regular expression d to match consecutive d characters (no limit to the number) . Finally, we use the FindAllString function to find all substrings that match the regular expression from the string and print the results.

Through the above examples, we can see that it is very simple to use regular expressions to match consecutive repeated characters in the Go language. You only need to define the matching rules and then use the functions provided by the regular expression library for matching.

To summarize, regular expressions are a powerful tool that can help us match, find and replace the required content in strings. In Go language, you can easily manipulate strings through the regular expression library. To match consecutive repeated characters, you only need to define the matching rules and then use the functions provided by the regular expression library to match. I hope this article will help you use regular expressions to match consecutive repeated characters in Go language.

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