Home  >  Article  >  Backend Development  >  php获取文件夹路径内的图片以及分页显示示例_PHP

php获取文件夹路径内的图片以及分页显示示例_PHP

WBOY
WBOYOriginal
2016-06-01 11:55:291161browse

复制代码 代码如下:


        $page=isset($_GET['page'])?$_GET['page']:0;//从零开始
    $imgnums = 10;    //每页显示的图片数
    $path="upload";   //图片保存的目录
    $handle = opendir($path);
    $i=0;
    while (false !== ($file = readdir($handle))) {
       list($filesname,$ext)=explode(".",$file);
       if($ext=="gif" or $ext=="jpg" or $ext=="JPG" or $ext=="GIF" ) {
           if (!is_dir('./'.$file)) {
              $array[]=$file;//保存图片名称
              ++$i;
           }
       }
    }

    if($array){
       rsort($array);//修改日期倒序排序
    }
    for($j=$imgnums*$page; $j       echo '

';
       echo $array[$j],'
';
       echo "php获取文件夹路径内的图片以及分页显示示例_PHP
";
       echo '
';
    }
    $realpage = @ceil($i / $imgnums) - 1;
    $Prepage = $page-1;
    $Nextpage = $page+1;
    if($Prepage       echo "上一页 ";
       echo "下一页 ";
       echo "最末页 ";
    }elseif($Nextpage >= $realpage){
       echo "首页 ";
       echo " 上一页 ";
       echo " 下一页";
    }else{
       echo "首页 ";
       echo "上一页 ";
       echo "下一页 ";
       echo "最末页 ";
    }
    ?>

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn