How to convert hexadecimal to binary in go language

Steps for converting Go language hexadecimal to binary: 1. Create a table corresponding to hexadecimal and binary; 2. Traverse the hash character by character and convert a single character into binary; 3. Fill in if it is less than 4 digits , using binary to represent hexadecimal requires 4 digits; 4. Just combine them in order.

There are many ways to implement it, such as creating a table corresponding to hexadecimal and binary, traversing and querying the hash strings one by one and then combining them.

I used another method here. The general idea is as follows:

• Traverse the hash character by character and convert a single character into binary;

• If it is less than 4 digits, fill it; (2^4 = 16, using binary to represent hexadecimal requires 4 digits)

• Combine in order;

Code example:

package util
import(
"strings"
"strconv"
)
func hash2bin(hash string)(string,int,error){
binary_string := ""
for _, char := range hash{
char_hex,err:= strconv.ParseInt(string(char),16,8)
if err!=nil{
return "",0,err
}
char_bin := ""
for ; char_hex > 0; char_hex /=2{
b := char_hex % 2
char_bin = strconv.Itoa(int(b))+char_bin
}
fill := 4-len(char_bin)
for fill>0{
char_bin = "0" + char_bin
fill -= 1
}
binary_string += char_bin
}
return binary_string,len(binary_string),nil
}

The above is the detailed content of How to convert hexadecimal to binary in go language. For more information, please follow other related articles on the PHP Chinese website!